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jeka57 [31]
1 year ago
10

Once a peptide has been formed between the amino acid attached to the trna in the p site and the amino acid associated with the

trna in the a site, which process on the list occurs next?.
Chemistry
1 answer:
nevsk [136]1 year ago
7 0

The complex known as RIBOSOME, which is made up of enzymes and ribosomal RNA, is where translocation peptide has indeed been generated.

What age is the ideal time to begin taking peptides?

Since collagen production normally slows down in your mid-20s to early-30s, I advise incorporating a peptide into your skincare regimen about this time. But regardless of your age, incorporating a peptide into your skincare regimen will make your skin look younger.

Peptide vs. protein: what are they?

In general, small chains of more than two amino acids are referred to as peptides. Proteins, commonly known as polypeptides, are lengthy molecules comprised of many peptide subunits. Enzymes (other proteins) can break down proteins into little peptide fragments.

To know more about peptide visit:

brainly.com/question/14902522

#SPJ4

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CH4 + O2 → CO2 + H2O
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Answer:

9.8 × 10²⁴ molecules H₂O

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Organic</u>

  • Naming carbons

<u>Stoichiometry</u>

  • Analyzing reaction rxn
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[RxN - Unbalanced] CH₄ + O₂ → CO₂ + H₂O

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 130 g CH₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[RxN] 1 mol CH₄ → 2 mol H₂O

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of H: 1.01 g/mol

Molar Mass of CH₄: 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up conversion:                                                                                   \displaystyle 130 \ g \ CH_4(\frac{1 \ mol \ CH_4}{16.05 \ g \ CH_4})(\frac{2 \ mol \ H_2O}{1 \ mol \ CH_4})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 9.75526 \cdot 10^{24} \ molecules \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

9.75526 × 10²⁴ molecules H₂O ≈ 9.8 × 10²⁴ molecules H₂O

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