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jeka57 [31]
1 year ago
10

Once a peptide has been formed between the amino acid attached to the trna in the p site and the amino acid associated with the

trna in the a site, which process on the list occurs next?.
Chemistry
1 answer:
nevsk [136]1 year ago
7 0

The complex known as RIBOSOME, which is made up of enzymes and ribosomal RNA, is where translocation peptide has indeed been generated.

What age is the ideal time to begin taking peptides?

Since collagen production normally slows down in your mid-20s to early-30s, I advise incorporating a peptide into your skincare regimen about this time. But regardless of your age, incorporating a peptide into your skincare regimen will make your skin look younger.

Peptide vs. protein: what are they?

In general, small chains of more than two amino acids are referred to as peptides. Proteins, commonly known as polypeptides, are lengthy molecules comprised of many peptide subunits. Enzymes (other proteins) can break down proteins into little peptide fragments.

To know more about peptide visit:

brainly.com/question/14902522

#SPJ4

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fredd [130]

Answer:

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Explanation:

Hope this helps

8 0
2 years ago
Is aluminum homogeneous or heterogeneous?
inn [45]
<span> aluminum is an element. All elements are pure substances, so that means they are homogenous.
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8 0
4 years ago
Please help
Snezhnost [94]
Relatively few hydrogen atoms
5 0
3 years ago
What is the volume of 33.25g of butane gas at 293 C and 10.934 kPa?
PSYCHO15rus [73]

Answer:

V = 240.79 L

Explanation:

Given data:

Volume of butane = ?

Temperature = 293°C

Pressure = 10.934 Kpa

Mass of butane = 33.25 g

Solution:

Number of moles of butane:

Number of moles = mass/ molar mass

Number of moles = 33.25 g/ 58.12 g/mol

Number of mole s= 0.57 mol

Now we will convert the temperature and pressure units.

293 +273 = 566 K

Pressure = 10.934/101 = 0.11 atm

Volume of butane:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

V = nRT/P

V = 0.57 mol × 0.0821 atm.L/ mol.K  ×566 K  / 0.11 atm

V = 26.49 L/0.11

V = 240.79 L

6 0
3 years ago
A sample of paper from an ancient scroll was found to contain 39.5% 14C content as compared to a present-day sample. The t1/2 fo
nirvana33 [79]

Answer

7665 years

Procedure

Let N₀ be the amount of carbon-14 present in a living organism. According to the radioactive decay law, the number of carbon-14 atoms, N, left in a dead tissue sample after a certain time, t, is given by the exponential equation:

N = N₀e^(-λt)

where λ is the decay constant which is related to half-life (T1/2) by the equation:

\lambda=\frac{ln(2)}{t_{\frac{1}{2}}}

Here, ln(2) is the natural logarithm of 2.

The percent of carbon-14 remaining after time t is given by N/N₀.

Using the first equation, we can determine λt.

The half-life of carbon-14 is 5,720 years, thus, we can calculate λ using the second equation, and then find t.

\lambda=\frac{ln(2)}{5720}=1.211\times10^{-4}

Solving the second equation for t, and using the λ we have just calculated we will have

t= 7665 years

3 0
1 year ago
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