Strontium phosphate reacts with sulfuric acid to form strontium sulfate and phosphoric acid. what is the coefficient for sulfuri
2 answers:
<u>Answer:</u> The coefficient of sulfuric acid in the given equation is 3.
<u>Explanation:</u>
The chemical equation for the reaction of strontium phosphate and sulfuric acid follows:
By Stoichiometry of the reaction:
1 mole of strontium phosphate reacts with 3 moles of sulfuric acid to produce 3 moles of strontium sulfate and 2 moles of phosphoric acid.
The given reaction is a type of double displacement reaction because here exchange of ions takes place.
Hence, the coefficient of sulfuric acid in the given equation is 3.
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Answer:
\large \boxed{\textbf{609 kJ}}
Explanation:
The formula for the heat absorbed is
q = mCΔT
Data:
m = 2.07 kg
T₁ = 23 °C
T₂ = 191 °C
C = 1.75 J·°C⁻¹g⁻¹
Calculations:
1. Convert kilograms to grams
2.07 kg = 2070 g
2. Calculate ΔT
ΔT = T₂ - T₁ = 191 - 23 = 168 °C
3. Calculate q
Answer:
Explanation:
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In this case, since the molarity is defined as moles of solute divided by liters of solution, since we have phenol with a molar mass of 94.12 g/mol, we can first compute the moles in 1.5 g of phenol:
Next, since 1000 mL = 1 L, we notice that the volume of the solution is 0.100 L and therefore, the molarity of such solution turns out:
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Answer:
Explanation:
First write the balance eqation of chemical reaction:
Remember writing any chemical reaction from its elemetal form then write the elements in their natural form i.e. how that element exists in the nature here sulphur exists in solid monoatomic form in the nature and oxygen in gaseous diatomic form.
mass of oxygen given=5gram
mole of oxygen
mass of sulpher given=6gram
mole of sulpher
from the above balanced equaion;
2 mole of sulphur reacts with 3 mole Oxygen completely
1 mole of sulphur reacts with 1.5 mole Oxygen completely
0.19 mole of sulphur reacts with i.e. 0.285 mole Oxygen completely.
but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent
so product will depend on the limiting reagent
from the balance equation
3 mole of sulpher gives 2 mole
1 mole of sulpher will give 2/3 mole
0.16 of sulpher will give 0.12 mole
mass of =9.6gram this is theoreical production of
and
actual production of =7.9gram