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lisabon 2012 [21]
3 years ago
5

Who could help me solve this

Mathematics
2 answers:
Monica [59]3 years ago
6 0
6561 hope this helps 
Elis [28]3 years ago
6 0
You would turn the -9 into a 9 and multiple 9x9x9x9 so 81 x81 is 6,561 hope it helps
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Cali soccer practice was one hour and 15 minutes long it ended at 7:15 PM what time did practice start
madreJ [45]

Answer:

Soccer practice started at 6:00, because 7:15 - 1:15 = 6:00

5 0
3 years ago
A doctor's office has a computer file showing the heights of 100 male patients of one of the doctors of the practice. the height
kumpel [21]
A) Yes. we don't have enough information so this can not be determined.
B) No, it would just be an outlier.
7 0
2 years ago
Solve the following dividend problem.
brilliants [131]

A.

To get dividend per share, we need to divide total dividend by total numbers of shares outstanding.

Dividend per share = \frac{40,000}{50,000}=0.8 dollars.


B.

Since per share you get $0.8, for 100 shares you will get 0.8*100=80 dollars.

Also, that is \frac{80}{40,000}*100=0.2 percent of the total dividends.


ANSWER:

A. $0.8 per share

B. $80 (and that is 0.2% of total dividend)

7 0
3 years ago
Read 2 more answers
Tom's stockbroker offers an investment that is compounded continuously at an annual interest rate of 3.7%. If Tom wants a return
Anettt [7]

Answer:

It'll take 38.3 years to obtain the desired return of $25,000.

Step-by-step explanation:

In order to solve a continuosly coumponded interest question we need to apply the correct formula that is given bellow:

M = C*e^(r*t)

Where M is the final value, C is the initial value, r is the interest rate and t is the time at which the money was applied. Since he wants an return of $25,000 his final value must be the sum of the initial value with the desired return. So we have:

(25000 + 8000) = 8000*e^(0.037*t)

33000 = 8000*e^(0.037*t)

e^(0.037*t) = 33000/8000

e^(0.037*t) = 4.125

ln[e^(0.037*t)] = ln(4.125)

t = ln(4.125)/(0.037)

t = 1.4171/0.037 = 38.2991

t = 38.3 years

7 0
3 years ago
5a - 24b =-15<br> 10a + 45c =21<br> 48b + 35c = 49
andrew-mc [135]

5a + 15 = 24b so,

10a + 30 = 48b,

sub to third equation,

10a + 30 + 35c = 49

10a + 35c = 19

perform elimination with second equation

10a + 45c = 21

10a + 35c = 19

________________-

10c = 2

c = 1/5

sub to second equation,

10a + (45)(1/5) = 21

10a + 9 = 21

10a = 12

a = 6/5

sub to first equation

(5)(6/5) - 24b = -15

6 + 15 = 24b

21 = 24b

b = 7/8

redo the calculations, correct me if I'm wrong

6 0
3 years ago
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