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3 years ago

Which point is in the graphed solution set of this system of inequalities?

Mathematics

1 answer:

tekilochka [14]3 years ago

8 0

Answer:

(2,-1)

4 over 3 on a gragh divided by the demonitar of the higher number equaled to 5 will get u (2,-1)

Step-by-step explanation:

Hopefully this helped, have a great day! :)

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Does 3 Quarters 3 nickels and 1 dime make $1.00

lidiya [134]

Answer:

91 cents

Step-by-step explanation: 3 times 25 is 75

3 times 5 is 15 then 1 so add to together

8 0

3 years ago

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1. In a factory, all employees work a basic week of 38 hours. Any overtime worked during week-days is paid for at time and a hal

Troyanec [42]

Answer:

Step-by-step explanation:

1. reg pay: 8.96,week days: 1.5 overtime pay, sat: double pay, sun: triple pay

38 hrs regular pay : 38 * 8.96 = 340.48

15 hrs overtime during week : 15 * 1.5(8.96) = 15 * 13.44 = 201.60

3 hrs overtime on saturday: 3 * 2(8.96) = 3 * 17.92 = 53.76

2 hrs overtime on sunday: 2 * 3(8.96) = 2 * 26.88 = 53.76

Gross wage = (340.48 + 201.60 + 2(53.76) = 649.60 <====

===============================

2. reg pay : 14.60, weekday pay: 1.25,sat pay: 1.5 , sun pay: double

(a) basic wage = 40(14.60) = 584 <==

(b) overtime wage : 15 * 1.25(14.60) + 6 * 1.5(14.60) + 5 * 2(14.60) = (15 * 18.25) + (6 * 21.9) + (5 * 29.2) = 273.75 + 131.40 + 146 = 551.15 <==

================================

3. basic work wk: 40 hrs...earned 518...overtime 148

(a) basic pay rate : (518 - 148) / 40 = 370/40 = 9.25 per hr <==

(b) if overtime is paid for at double time.....so overtime pay is (2 * 9.25) = 18.50 per hr....and he got paid 148....148/18.5 = 8 hrs <==

4 0

3 years ago

A team of runners is needed to run a 1/3-mile relay race. If each runner must run 1/9 mile, how many runners will be needed?

Alex Ar [27]

Answer:

3 Runners

Step-by-step explanation:

6 0

3 years ago

PLSS HELP!! VERY EASY.

gogolik [260]

Answer:

35 ways

Step-by-step explanation:

Alex has 9 friends and wants to invite 5 friends. Since Alex requires two of his friends who are twins to come together to his birthday party, since the two of them form a group, the number of ways we can select the two of them to form a group of two is ²C₂ = 1 way.

Since we have removed two out of the nine friends, we are left with 7 friends. Also, two friends are already selected, so we are left with space for 3 friends. So, the number of ways we can select a group of 3 friends out of 7 is ⁷C₃ = 7 × 6 × 5/3! = 35 ways.

So, the total number ways we can select 5 friend out of 9 to party come to the birthday include two friends is ²C₂ × ⁷C₃ = 1 × 35 = 35 ways

3 0

3 years ago

Kendra’s work is shown in the table. Where, if anywhere, did Kendra first make a mistake? Steps Kendra’s Work Step 1 Negative 3

natali 33 [55]

Answer:

C : STEP 3

Step-by-step explanation:

JUST DID THIS EQUATION AND GOT IT RIGHT HOPE THIS HELPS

4 0

4 years ago

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