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Alborosie
4 years ago
6

This formula equation is unbalanced. BaCl2(aq) + Na2CO3(aq) mc017-1.jpg BaCO3(s) + NaCl(aq) Which coefficient should be placed i

n front of NaCl to balance this equation? 1 2 3 4
Chemistry
2 answers:
Nookie1986 [14]4 years ago
8 0
You would need to put a 2 in front of NaCl.

Hope this helps!!
~Kiwi
Lady_Fox [76]4 years ago
5 0

BaCl2(aq)  + Na2CO3(aq)  → BaCO3 (s)  + NaCl(aq)

The coefficient that  should  be  placed in front  of NaCl  to balance the equation above  is 2

The balanced equation  is as below

BaCl(aq)  + Na2CO3 (aq)→ BaCO3 (s)  + 2NaCl (aq)


<u><em>Explanation</em></u>

According to law of mass conversation the number of atoms  of an element  must be equal  in both side of reaction.

By adding 2  in front of NaCl ensures that  the number  of each element  is equal  in both side.

for example there  is 2 atoms  of Na in both reactant and product side.

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xenn [34]
1 is b 2 is a 3 is d 4 is a 5 is c
5 0
3 years ago
Pls help me <br><br> What is the mass in grams of 2.64 mol of sulfur dioxide, SO2?
notsponge [240]

Answer: The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles SO2, or 64.0638 grams.

Hope it helps.

8 0
3 years ago
If you have 250 mL of 0.75 M LINO2.<br> How many grams of this substance<br> would you have?
Vesna [10]

Mass of this substance = 9.928 g

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

\boxed{\bold{n=V\times M}}

mol of substance -Lithium nitrite - LiNO₂ :

V = 250 ml = 0.25 L

M = 0.75 M

\tt n=0.25\times 0.75=0.1875

So mass of this substance -  LiNO₂ (MW=52,947 g/mol) :

\tt mass=mol\times MW\\\\mass=0.1875\times 52,947 g/mol\\\\mass=9.928~g

4 0
3 years ago
Give the n and l values and the number of orbitals for sublevel 5g.
Pepsi [2]

The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

There are total four quantum numbers:

1) Principal quantum number , n

2) Angular quantum number , l

3) Magnetic quantum number , ml

4) spin quantum number , ms

For 5g shell, n = 5

subshell g , l = 4     ....0 - s , 1 - p , 2 - d, 3 - f, 4 -g

number of orbitals in subshell = (2l + 1)  ( 2×4 + 1) = 9

Thus,  The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

To learn more about quantum numbers here

brainly.com/question/14650894

#SPJ1

6 0
1 year ago
What is true of diffusion
Fed [463]

Molecules move from areas of high concentration to areas of low concentration.

7 0
3 years ago
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