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Ugo [173]
3 years ago
10

What is a solution?

Chemistry
2 answers:
Shalnov [3]3 years ago
3 0
<span>A means of solving a problem or dealing with a difficult situation.

</span>
Leno4ka [110]3 years ago
3 0
It's a noun.
A means of solving a problem or dealing with a difficult situation
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Yanka [14]

Answer:

Hey, I don't know but try 10+ (h) + 5 ), 79

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How are cellular respiration and photosynthesis related?
jekas [21]

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A

Explanation:

Hope it helps

<em> </em><em>#CarryOnLearning</em><em> </em>

3 0
3 years ago
A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

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4 years ago
Explain how boiling and evaporating are alike and how they are differant
julsineya [31]

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4 years ago
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3 years ago
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