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Ugo [173]
3 years ago
10

What is a solution?

Chemistry
2 answers:
Shalnov [3]3 years ago
3 0
<span>A means of solving a problem or dealing with a difficult situation.

</span>
Leno4ka [110]3 years ago
3 0
It's a noun.
A means of solving a problem or dealing with a difficult situation
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Using Argn (n= –2, –1, 0, +1, +2, etc.) to represent the different charge species of Arginine, what is the dominant species of A
fredd [130]

Answer:

Explanation:

From the sorensen equation; pH = -Log[H+]

2.7 = -Log[H+]

H+ = 10^-2.7

H+ = 0.001995M = Hydrogen ion concentration

Basically, the more the charges, the higher the hydrogen ion concentration stand vice versa. +2 has the highest concentration.

6 0
2 years ago
Need help !!!!! ASAP
Ksivusya [100]
<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of CO_{2}

n=0.120mol

<h2>Why?</h2>

We are asked to calculate the number of moles of the given gas, also, we  are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

R=62.363\frac{mmHg.L}{mol.K}

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°) + 273K

So, we are given the following information:

Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K

Now, isolating the number of moles, and substituting the given information, we have:

PV=nRT

n=\frac{PV}{RT}

n=\frac{PV}{RT}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole

Hence, we have that there were produced 0.120 moles of CO_{2}

n=0.120mol

Have a nice day!

7 0
3 years ago
Calcium cyclamate, Ca(C₆H₁₁NHSO₃)₂, is an artificial sweetener used in many countries around the world but is banned in the Unit
xeze [42]

Answer:

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃;

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃;

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

Explanation:

First, let's see the reactants for the first reaction and how they dissociate:

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

BaCO₃ → Ba²⁺ + CO₃²⁻ (Barium is from group 2, so its cation has charge +2)

So, to form the products, the cation of one will join the anion of others. The amount of the cation will be the charge of the anion, and the amount of the anion will be the charge of the cation:

H⁺ + CO₃²⁻ → H₂CO₃

Ba²⁺ + C₆H₁₁NHSO₃⁻ → Ba(C₆H₁₁NHSO₃)₂

The reaction then is:

HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The number of elements must be the same on both sides, so the balanced equation is

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The treatment with H₂SO₄ will produce:

H₂SO₄ → 2H⁺ + SO₄⁻²

Ba(C₆H₁₁NHSO₃)₂ → Ba²⁺ + C₆H₁₁NHSO₃⁻

The balanced reaction will be then:

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃

In the last step, HC₆H₁₁NHSO₃ will react with Ca(OH)₂

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

Ca(OH)₂ → Ca²⁺ + 2OH⁻

The balance reaction will be:

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

3 0
3 years ago
PLEASE HELP I NEG YOU FATHERCARRAS PLEASE HELP ME !!!
LekaFEV [45]
Answer 
<span>How does adding a non-volatile solute to a pure solvent affect the vapor pressure of the pure solvent?

</span>Answer The third option The solvent's vapor pressure will not be affected.

<span>To make a 2.0 M solution, how many moles of solute must be dissolved in 0.50 liters of solution?

Answer C. 1.0 mole solute.
</span>
3 0
3 years ago
Which of the following solutions would have the lowest freezing point?
Paul [167]

B. 3.0 mol·L⁻¹ NaCl

Explanation:

Freezing point is a colligative property: it depends only on the number of particles in solution.

The for freezing point depression ΔT_f is

ΔT_f = iK_fb

where

i = the number of moles of particles available from one mole of solute

K_f = the molal freezing point depression constant

b = the molal concentration of the solute

All your solutions are aqueous NaCl. They differ only in their concentrations.

Thus, the most concentrated solution will have the greatest freezing point depression and the lowest freezing point.

Read more on Brainly.com - brainly.com/question/11516173#readmore

4 0
3 years ago
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