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xz_007 [3.2K]
3 years ago
11

Indicate type of chemical reactions for 2Mgl2+MN(SO3)2=2MgSO3+Mnl4​

Chemistry
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

double decomposition reaction

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P4 (s) + 5O2 (g) ⟶ P4 O10(s) ΔG° = −2697.0 kJ/mol 2H2 (g) + O2 (g) ⟶ 2H2 O(g) ΔG° = −457.18 kJ/mol 6H2 O(g) + P4 O10(s) ⟶ 4H3 PO
aalyn [17]

Answer:

the standard free energy of formation of phosphoric acid H3 PO4 is -1010 kJ/mol

Explanation:

Knowing that

1) P4 (s) + 5O2 (g) ⟶ P4 O10(s) ΔG° = −2697.0 kJ/mol

2) 2H2 (g) + O2 (g) ⟶ 2H2 O(g) ΔG° = −457.18 kJ/mol

3) 6H2 O(g) + P4 O10(s) ⟶ 4H3 PO4 (l) ΔG° = −428.66 kJ/mol

since

ΔG° reaction = ν * ΔGf °  products - v *ΔGf °  reactives

for reaction 1

ΔG° = ∑ν * ΔGf °  products - ∑v *ΔGf °  reactives

ΔG° = 1 *ΔGf ° P4 O10 - ( 5 *ΔGf ° O2 + 1 *ΔGf ° P4)

ΔG° = ΔGf ° P4 O10 - (5*0 +1*0)

ΔGf ° P4 O10 = ΔG° = −2697.0 kJ/mol

for reaction 2

ΔG° = ∑ν * ΔGf °  products - ∑v *ΔGf °  reactives

ΔG° = 2 *ΔGf ° H20 - ( 1*ΔGf ° O2 + 2 *ΔGf ° H2)

ΔG° = 2* ΔGf ° H20 - (1*0 +2*0)

ΔGf ° H20 = ΔG° /2  = -457.18 kJ/mol/2 = -228.59 kJ/mol

for reaction 3

ΔG° = ∑ν * ΔGf °  products - ∑v *ΔGf °  reactives

ΔG° = 4 *ΔGf ° H3 PO4 - ( 6*ΔGf ° H2O + 1*ΔGf ° P4O10)

−428.66 kJ/mol = 4 *ΔGf ° H3 PO4 - [ 6*(-228.59 kJ/mol) + 1*(−2697.0 kJ/mol)]

−428.66 kJ/mol = 4 *ΔGf ° H3 PO4 + 3611.36 kJ/mol

ΔGf ° H3 PO4 = (−428.66 kJ/mol - 3611.36 kJ/mol)/4 = -1010 kJ/mol

6 0
3 years ago
Please check my answer! Due in a few minutes!
rewona [7]

Answer:

Explanation:

It is A. that is the only one that really makes any sense to me.

I do hope I helped you! :)

8 0
3 years ago
Read 2 more answers
Fluorine (F) and bromine (Br) are in the same group on the periodic table. How do atoms of these elements compare when they form
sertanlavr [38]

Answer:

Both a fluorine atom and a bromine atom gain one electron, and both atoms become stable.

Explanation:

The two elements compare when they form bonds in that when both a fluorine atom and a bromine atom gain one electron, they both become stable.

  • Fluorine and bromine are elements called halogens.
  • They both belong to group 7 on the periodic table.
  • When they gain an electron each, they become isoelectronic with a corresponding noble gas.
  • This gives their atom special stability.
3 0
3 years ago
Read 2 more answers
Which of the following reactions is correctly balanced?
Kitty [74]
I believe it is 3 CA + 1 N2 -> Ca3N2; I cannot tell whether the O(s) in front of the next three are supposed to be oxygens, if so then yes definitely the first line is correctly balanced.
7 0
3 years ago
The information below describes a redox reaction.
Vera_Pavlovna [14]

3

Explanation:

The coefficient in the final, balanced equation for the reaction is 3.

Now let us look into the reaction:

  The half equations are;

  Ag⁺ +  e⁻ →  Ag   reduction half

  Al   →   Al³⁺  +  3e⁻ oxidation half

The reduction half, electron is taken in where as in the oxidation half, electron is lost.

  To derive the over all balanced equation;

             Ag⁺ +  e⁻ →  Ag     multiply by 3

           Al   →   Al³⁺  +  3e⁻   multiply by 1

This gives :

            3Ag⁺ +  3e⁻ →  3Ag

             Al   →   Al³⁺  +  3e⁻

Adding reactants together and products together:

              3Ag⁺ +  3e⁻  +  Al      →     3Ag   +  Al³⁺  +  3e⁻

Cancel out species that appears on both sides of the expression because they are spectators:

              3Ag⁺_{aq}   +  Al_{s}       →     3Ag_{s}    +  Al³⁺  _{aq}

We see that silver has a coefficient of 3 in the balanced expression.

learn more:

Ionic equation brainly.com/question/2947744

#learnwithBrainly

6 0
4 years ago
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