Answer:
ΔQ = 11050.2 J
Explanation:
Assume mass of pan is 900 gm
Assuming mass of water is 100 gm
Assuming initial temperature of pan & water is Ti = 51.268 degree C
The final temperature is T_f = 77.7 degree C
The total energy required to raise temperature
E = [(900)(0.9) + (100)(4.2)](26.44)
E = 32521.2 J
The energy transferred is given by
ΔQ = E-W
ΔQ = 32521.2 J - 21471 J
ΔQ = 11050.2 J