Question

Calculate the approximate volume of a 0.600 mol sample of gas at 15.0°c and a pressure of 1.10 atm.

Answer 1

Answer:

$0.0129 m^3$

Explanation:

The volume of the gas can be used by using the ideal gas equation:

$pV=nRT$

where

p is the gas pressure

V is the gas volume

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have

p = 1.10 atm is the pressure

V = ? is the volume

n = 0.600 mol is the number of moles

R = 0.082 L/atm K mol is the gas constant

T = 15.0 C + 273 = 288 K is the absolute temperature

Solving the equation for V, we find

$V=\frac{nRT}{p}=\frac{(0.600 mol)(0.082 L/atm mol K)(288 K)}{1.10 atm}=12.9 L$

and converted into meters cubed, it is

$V=12.9 L = 0.0129 m^3$