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3 years ago

What is the direction of magnetic field lines inside any magnet

Physics

2 answers:

Savatey [412]3 years ago

7 0

North and South is the correct answer, correct me if I am wrong

Eduardwww [97]3 years ago

7 0

Magnetic field lines are the imaginary lines which are nothing else than the pictorial representation of the field.

A magnet has always two poles. Mono pole magnet does not exist in nature.The two poles of a magnet are known as south pole and north ole.

The magnetic filed lines originate from the north pole of a magnet. Unlike electric field lines, magnetic field lines form close loop.The direction of magnetic filed lines are from north pole to south pole outside of the magnet. The direction will be reversed inside the magnet i.e it will be directed from south to north.

Hence, the direction of the magnetic field lines are from south pole to north pole inside any magnet.

You might be interested in

The observed standard penetration test value in a deposit of fully submerged sand was 45 at a depth of 6 m. The average submerge

exis [7]

Answer:

43.54

Explanation:

Effective overburden pressure will be $6m\times 9.7=58.2 kN/m^{2}$

Overburden correction is given by

$C_N= \sqrt{\frac {95.76}{p_o}}$

Where and are effective overburden pressure and overburden correction

Substituting the value of overburden pressure then

$C_N= \sqrt{\frac {95.76}{58.2}}= 1.282716\approx 1.28$

Taking hammer efficiency of 0.8, drill rod length correction factor of 0.9 and borehole correction factor of 1.05 then corrected SPT value will be

$45*1.28*0.8*0.9*1.05\approx 43.54$

4 0

3 years ago

Savanna regions developed during the Triassic period.

stich3 [128]

The answer is : true

5 0

1 year ago

Study the concentration amount shown on the juice label. Then answer the question. If you had 100 mL of juice, how many millilit

umka21 [38]

The answer is 25 ml for this question

8 0

4 years ago

a brick of mass of 1 kg and density 2.5gm/cm³ is immersed in water how much mass of water is displace by it.

Daniel [21]

Answer:

1 kg

Explanation:

.suebebdindnwb....

6 0

3 years ago

I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......

pav-90 [236]

Answer:

Explanation:

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

100 $cm^{2}$ x 10cm = 1000 $cm^{3}$

Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....

$\frac{1g}{cm^{3} }$ x 1000 $cm^{3}$ = 1000g or 1kg

Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....

1000g + 100g = 1100g or 1.1kg

The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

20g ÷ $\frac{8g}{cm^{3} }$ = 2.5 $cm^{3}$

Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5 $cm^{3}$ overflowed. So now we the same process as in number a) just with a few adjustments.

$\frac{1g}{cm^{3} }$ x (1000 $cm^{3}$ - 2.5 $cm^{3}$ ) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.

100g + 997.5g + 20g = 1117.5g or 1.1175kg

5 0

3 years ago