Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
6x+1 = 3(2x-4)
-4(x+3) = 4(x-1)
I think it’s b I hope I’m sosososososos sorry if it ain’t
Slope = (y2 - y1) / (x2 - x1)
(-9,6)....x1 = -9 and y1 = 6
(-3,9)...x2 = -3 and y2 = 9
now we sub and solve
slope = (9 - 6) / (-3 - (-9) = 3 / (-3 + 9) = 3/6 = 1/2 <=
