Answer: The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since, 11 + 21 > 16, 11 + 16 > 21, and 16 + 21 > 11, you can form a triangle with side lengths 11 mm, 21 mm, and 16 mm.
Step-by-step explanation:
9514 1404 393
Answer:
D 2.14
Step-by-step explanation:
The lengths of interest are the hypotenuses of the respective triangles. We are given the angle and the opposite side, so the sine relation is of interest.
Sin = Opposite/Hypotenuse
sin(34°) = AC/AB ⇒ AB = AC/sin(34°)
sin(53°) = AC/AD ⇒ AD = AC/sin(53°)
The desired difference in lengths is ...
AB -AD = AC(1/sin(34°) -1/sin(53°)) = 4(1.78829 -1.25214) ≈ 2.1446
The difference in lengths is about 2.14 units.
Answer:
Step-by-step explanation:
take lcm of (2x-1)(x+2)
lcm=(2x-1)(x+2)
=2(x+2)-1(2x-1)/(2x-1)(x+2)
=(2x+4)-(2x-1)/(2x(x+2)-1(x+2)
=2x+4-2x+1/2x^2+4x-x+2
=4+1/2x^2+3x+3
=5/2x^2+3x+3
Answer:

Step-by-step explanation:
-The cumulative area of the six is equivalent to the sum of their individual areas.
-Area of a triangle is given by:

We substitute given values in the equation and multiply by the number of pennants:

Hence, the total area needed is 
Answer:
.69, but you can round it to .70 because of the 9
Step-by-step explanation:
70%