Question

determine the hydrogen ion concentration of .650 M aqueous solution of NaOH. the ionization product constant for water, Kw, is 1.00*10^-14

Answer 1

When Kw = [H+] [OH-]  

when Kw is the ion-product constant for water = 1 x 10^-14

and [H+] is the hydrogen concentration (which we need to calculate)

and [OH-] = 0.65 M 

so by substitution:

1 x 10^-14 = [H+] * 0.65

∴[H+] = 1.54 x 10^-14 m