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pickupchik [31]
3 years ago
11

determine the hydrogen ion concentration of .650 M aqueous solution of NaOH. the ionization product constant for water, Kw, is 1

.00*10^-14
Chemistry
1 answer:
olga2289 [7]3 years ago
8 0
When Kw = [H+] [OH-]  

when Kw is the ion-product constant for water = 1 x 10^-14

and [H+] is the hydrogen concentration (which we need to calculate)

and [OH-] = 0.65 M 

so by substitution:

1 x 10^-14 = [H+] * 0.65

∴[H+] = 1.54 x 10^-14 m
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