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3 years ago

How the Atmosphere affects the Biosphere pls help

Chemistry

1 answer:

guapka [62]3 years ago

6 0

Answer:

Explanation:

Air pollutants also affect the biosphere in turn. Ozone and acid deposition suppress plant growth; meanwhile, aerosols and their indirect effects on clouds decrease total photosynthetically active radiation (PAR) while increasing the diffuse fraction.

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A solution prepared by mixing 10 ml of 1 m hcl and 10 ml of 1.2 m naoh has a ph of

blagie [28]

Answer: pH of resulting solution will be 13

Explanation:

pH is the measure of acidity or alkalinity of a solution.

Moles of $H^+$ ion = $Molarity\times {\text {Volume in L}}=1M\times 0.01L=0.01mol$

Moles of $OH^-$ ion = $Molarity\times {\text {Volume in L}}=1.2M\times 0.01L=0.012mol$

$HCl+NaOH\rightarrow NaCl+H_2O$

For neutralization:

1 mole of $H^+$ ion will react with 1 mole of $OH^-$ ion

0.01 mol of $H^+$ ion will react with = $\frac{1}{1}\times 0.01mole$ of $OH^-$ ion

Thus (0.012-0.01)= 0.002 moles of $OH^-$ are left in 20 ml or 0.02 L of solution.

$[OH^-]=\frac{0.002}{0.02L}=0.1M$

$pOH=-log[OH^-]$

$pOH=-log[0.1]=1$

$pH+pOH=14$

$pH=14-1=13$

Thus the pH of resulting solution will be 13

7 0

3 years ago

Predict the type of substitution mechanism predict which reaction of the pair will occur at a faster rate

Diano4ka-milaya [45]

You put in a variable to substitute the unknown number.

5 0

3 years ago

You measure the emission spectrum of an atom that you suspect to be hydrogen. You have no absolute calibration of the wavelength

trapecia [35]

Answer:

Explanation:

What we need to do here is to determine the ratios by using the Rydberg equation starting with the transition to n1 = 1, 2,3, etc and see which one fits the data. Remember the question states that they are series and the wavelengths will be for increasing energy levels.

1/λ = Rh x ( 1/n₁² - 1/n₂²)

Lyman series ( n₁=1 and n₂= 2,3 etc) for the first two lines, the ratios will be:

1/λ₁ /1/λ₂ =(1/1 -1/ 2²) / (1/1 -1/ 3²) ⇒ 0.84 ≠ 0.74 (the first ratio)

For Balmer series n₁ = 2 and n₂ = 3,4,5, etc

1/λ₁ /1/λ₂ =(1/4 -1/3²) / (1/4 -1/4²) ⇒ 0.741 = 0.741 (match!)

Lets use the third line to check our answer:

1/λ₁ /1/λ₂ =(1/4 -1/3²) / (1/4 -1/5²) = 0.66

5 0

3 years ago

Which of the following is a way that materials are used?

Svetach [21]

Answer:

the answer is B.Construction

Explanation:

8 0

3 years ago

Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 162. kJ during a certain chemical reaction, w

puteri [66]

Answer:

= -356KJ

<em>therefore, the reaction where heat is released is exothermic reaction since theΔH is negative</em>

Explanation:

given that enthalpy of gaseous reactants decreases by 162KJ and workdone is -194KJ

then,

change in enthalpy (ΔH) = -162( released energy)

work(w) = -194KJ

change in enthalpy is said to be negative if the heat is evolved during the reaction while heat change(ΔH) is said to be positive if the heat required for the reaction occurs.

At constant pressure the change in enthalpy is given as

ΔH = ΔU + PΔV

ΔU = change in energy

ΔV = change in volume

P = pressure

w = -pΔV

therefore,

ΔH = ΔU -W

to evaluate energy change we have,

ΔU =ΔH + W

ΔU = -162+ (-194KJ)

= -356KJ

<em>therefore, the reaction where heat is released is exothermic reaction since theΔH is negative</em>

6 0

3 years ago