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3 years ago

How is it possible to have thousands of different proteins when there are only 20 different amino acids?

1 answer:

3 0

Hi there!

Although there are only 20 amino acids, these amino acids can combine into an innumerable amount of combinations to form different and unique proteins.

In case that doesn't make sense to you, I'll provide you with an analogy. You could be provided with 20 different LEGO bricks to work with. While there may only be 20 bricks, these bricks can combine into a vast amount of different formations, structures, etc. Amino Acids work in the same way.

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A fat is composed, in part, of long chains of carbon and hydrogen. This fat as a molecular

IgorLugansk [536]

Answer:

$C_{54}H_{102}O_6$

Explanation:

Hello!

In this case, since the molar mass of the empirical formula is:

$MM_{empircal}=9*12.01+17*1.01+16.00=141.26g/mol$

Thus, the ratio of the molecular to the empirical formula is:

$\frac{847g/mol}{141.26g/mol} =6.0$

Thus, the molecular formula is six times the empirical formula:

$C_{54}H_{102}O_6$

Best regards!

8 0

3 years ago

The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equati

valkas [14]

Answer:

(a) $p_{C6H5CH2OH}=2.14x10^{-3}atm$

(b) $Dissociation =0.99$

Explanation:

Hello,

(a) In this case, for the given chemical reaction, the law of mass action becomes:

$Kc=\frac{[C6H5CHO][H2]}{[C6H5CH2OH]}$

In such a way, as 1.20 g of benzyl alcohol are placed into a 2.00-L vessel, the initial concentration is:

$[C6H5CH2OH]_0=\frac{1.20g*\frac{1mol}{108.14g} }{2.00L} =5.55x10^{-3}M$

Hence, by writing the law of mass action in terms of the change $x$ due to equilibrium:

$Kc=\frac{(x)(x)}{5.55x10^{-3}-x}=0.558$

Solving for $x$ by using a quadratic equation one obtains:

$x=5.50x10^{-3}M$

Thus, the equilibrium concentration of benzyl alcohol is computed:

$[C6H5CH2OH]_{eq}=5.55x10^{-3}M-5.50x10^{-3}M=5x10^{-5}M$

With that concentration the partial pressure results:

$p_{C6H5CH2OH}=[C6H5CH2OH]_{eq}RT =5x10^{-5}\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*523K \\p_{C6H5CH2OH}=2.14x10^{-3}atm$

(b) Now, the fraction of benzyl alcohol that is dissociated relates its equilibrium concentration with its initial concentration:

$Dissociation=\frac{C6H5CH2OH_{eq}}{C6H5CH2OH_0} =\frac{5.50x10^{-3}M}{5.55x10^{-3}M} =0.99$

Best regards.

3 0

3 years ago

Read 2 more answers

6. A 50-year-old sample of Strontium-90 is found. The half-life of strontium is 29

Gnesinka [82]

Answer:

the sample has mass of 50mg initially

Explanation:

https://youtu.be/ietdukGMG5c

8 0

3 years ago

antimony(III) sulfide is reacted with excess iron. if 175.6 grams of pure antimony is produced what mass of antimony sulfide was

Ad libitum [116K]

Answer: -

The chemical formula of Antimony(III) sulfide = Sb₂S₃

Mass of Sb produced = 175.6 g

Molar mass of Sb = 121.76 g /mol

Number of moles of Sb = 175.6g / (121.76 g/mol)

= 1.44 mol

The balanced chemical equation for this reaction is

Sb₂S₃ + 3 Fe → 2 Sb + 3 FeS

From the chemical equation we see

2 mol of Sb is produced from 1 mol of Sb₂S₃

1.44 mol of Sb is produced from $\frac{1 mol Sb2S3 x 1.44 mol Sb}{2 mol of Sb}$

= 0.72 mol of Sb₂S₃

Molar mass of Sb₂S₃ = 2 x 121.76 + 32.06 x 3

= 339.7 g / mol

Mass of Sb₂S₃ = 0.72 mol x 339.7 g/ mol

= 244.58 g

= 244.6 g rounded off to 4 significant figures.

5 0

4 years ago

What do u do when you butter in a tub melts i put it in my fridge but after 1 hour it has some kind of water in it or something

schepotkina [342]

Answer: not sure either. not sure what exactly your asking because the wording is weird. (no offense)

6 0

3 years ago