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leva [86]
3 years ago
15

A radio station had 120 tickets to a concert. They gave away 2 times as many tickets to listeners as to employees. How many tick

ets did they give away to employees?
Mathematics
1 answer:
enyata [817]3 years ago
8 0

Step-by-step explanation:

If the tickets given to employees = 40

Then tickets given to listeners = 2 x no of employees tickets

= 2 x40 = 80

Total tickets = 40+ 80 = 120

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x=2

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What is 13.989 to the nearest hundredth place?
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Answer:

13.99

Step-by-step explanation:

So the hundredths place is the second digit after the decimal point in this case it is 8.

So the number after it is 9 so we round up.

The number after 8 is 9

So 13.989 to the nearest hundredth place is 13.99

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A set of data collected to answer a statistical question has a distribution which can be described by its __________.
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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

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3 years ago
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Hatshy [7]

Answer:

Step-by-step explanation:

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6: x intercept (1,0)

y intercept is when the line intersect with y axis at certain point or when x=0

y intercept (0.-24)

22: (8,0) x intercept

(0 , 4) the y-intercept

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