Answer:
1210 N/m between the inner and outer edges (repulsive)
252.59 N/m between inner and line charges (attractive)
1210+252.59=1462.59 N/m effective force/metre on the inner edge
Explanation:
f=k*Qq/r^2 was applied, the charges are concentrated at the edges of a ring both inner and the outer were shape edges with uniform charge densities 6.6 micro C/m of distance 4.5-2.7=1.8 cm
Answer:
10seconds
Explanation:
use the formula a=v final_v inital/time
Answer:
Explanation:
The signals sent from the earth, travel at the speed of light, therefore the travel time of the signal between the earth and neptune, can be calculated with the following equation, which relates time, speed and distance:
The time elapsed is approximately 4.41 hours
V=D/T
V is speed
D is distance
T is time
V=D/T
31.67 m/s = 1361.81 m / T
31.67/31.67=1361.81/31.67
T=43 seconds
Hope this helps
The question is incomplete.
Here is the complete question (only part A):
Two children, Ferdinand and Isabella, are playing with
a water hose on a sunny summer day. Isabella is holding the hose
inher hand 1.0 meters above the ground and is trying to
spray Ferdinand, who is standing 10.0 meters away.
Part A
Will Isabella be able to spray Ferdinand
if the water is flowing out of the hose at a constant
speed Vo of 3.5
meters per second? Assume that the hose is pointed parallel to the
ground and take the magnitude of the acceleration due to gravity
to be 9.81 meters per second, per second.
Answer: No. Since the water jet runs 1.58 m before falling into the ground, it cannot spray Ferdinand who is 10.0 m away.
Explanation:
1) Data:
yo = 1.0m
Vox = 3.5 m/s
Voy = 0
x = 10.0 m
g = 9.81 m/s²
2) Type of motion and formulas
Parabolic motion
y = yo + Voy×t - g×t² / 2
x = Vox × t
3) Solution:
i) From y = yo + Voy×t - g×t² / 2 calculate t until the water reaches the ground (y = 0).
From the data yo = 1, and Voy = 0
0 = 1.0 - 4.905t² ⇒ t = √ (1.0 / 4.905) = 0.45 s
ii) Calculate x using t = 0.45s
From the data Vox = 3.5m/s
x = Vox × t = 3.5m/s × 0.45s = 1.58 m
iii) Conclusion: since the water jet runs 1.58 m before falling into the ground, it cannot spray Ferdinand who is 10.0 m away.