Gravitational potential energy, relative to some level =
(mass of the object)
times
(height above the reference level)
times
(acceleration due to gravity) .
Simply draw the vector with the given coordinates.
Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.
<h3>
What is the impulse of the speed bump?</h3>
- Impulse = change in momentum
- momentum = mass * velocity
Change in momentum = mu - mv
where u is initial velocity
v is final velocity
Impulse = 500 * 20 - 500 * 15
Impulse = 2500 Ns
Therefore, the impulse of the speed bump to the car is 2500 Ns.
Learn more about impulse at: brainly.com/question/297527
Answer:
775.48 W
Explanation:
given,
diameter of disk = 0.6 cm
length of the disk = 0.4 m
T₁ = 450 K T₂ = 450 K T₃ = 300 K
= 1.33
now,
the value of view factor (F₁₂)corresponding to 1.33
F₁₂ = 0.265
F₁₃ = 1 - 0.265 = 0.735
now,
net rate of radiation heat transfer from the disk to the environment:

= 2 F₁₃ A₁ σ (T₁⁴ - T₃⁴)
= 2 x 0.735 x π x (0.3)² x (5.67 x 10⁻⁸ W/m²) (450⁴ - 300⁴)
= 775.48 W
Net radiation heat transfer from the disks to the environment = 775.48 W
(2.5,-1) There you go bro