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FinnZ [79.3K]
4 years ago
11

Which magnetic property best describes a magnet’s ability to act at a distance?

Physics
2 answers:
blsea [12.9K]4 years ago
8 0
Magnetic field describea magnet's ability to act at a distance

Verizon [17]4 years ago
5 0
<span>Magnets have magnetic fields.</span>
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The mass of a body is 25 kg and the value of acceleration due to gravity is 9.8 m/s^2. Calculate the weight of body.​
maks197457 [2]

Explanation:

weight=mass ×acceleration

weight=25×9.8

=245

3 0
3 years ago
Read 2 more answers
If you could see stars during the day, the drawing above shows what the sky would look like at noon on a given day. The Sun is n
svetlana [45]

Answer:

Taurus constellation

Explanation:

Because Taurus constellation is mostly seen In the Northern Hemisphere, the bull passes through the sky from November to March, but the constellation's at its most visible in January. Taurus covers 797 square degrees.

Right ascension: 4 hours

Declination: 15 degrees

Best visible between latitudes 90 degrees and minus 65 degrees

6 0
3 years ago
What characteristic describes what happens during a physical change
Alex73 [517]
Physical change changes the form of a chemical substance
7 0
3 years ago
A pulley system has an efficiency of 74.2%. If you perform 200 J of work, how
Fudgin [204]

Answer:

C

Explanation:

If a pulley system has an efficiency of 74.2%, then only that fraction of the work performed will be useful. 74.2%=0.742. 0.742*200 is about 148J. Hope this helps!

8 0
3 years ago
A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are
igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

T = I\alpha = 0.303*0.6454 = 0.196 Nm

So the force acting on the other end to generate this torque mush be:

F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N

4 0
4 years ago
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