All categories

3 years ago

You throw a rock straight up into the air with a speed of 14.2 m/s. how long does it take the rock to reach its highest point?

1 answer:

4 0

The acceleration of gravity on or near the Earth's surface is 9.8 m/s² downward.
Is that right ? I don't hear any objection, so I'll assume that it is.

That means that during every second that gravity is the only force on an object,
the object either gains 9.8m/s of downward speed, or it loses 9.8m/s of upward
speed. (The same thing.)

If the rock starts out going up at 14.2 m/s, and loses 9.8 m/s of upward speed
every second, it runs out of upward gas in (14.2/9.8) = <em>1.449 seconds</em> (rounded)

At that point, since it has no more upward speed, it can't go any higher. Right ?

(crickets . . .)

You might be interested in

True or False. Where an element is located on the periodic table can help predict some of its properties.

lubasha [3.4K]

It’s true there are sections in the periodic table that define the elements.

7 0

3 years ago

Read 2 more answers

Describe Rutherford's contribution to the atomic model.

mamaluj [8]

Rutherford (1871–1937) was responsible for a remarkable<span> series of discoveries in the physics, especially in the atomic model.
</span>He identified the atomic nuclei - a relatively high central charge concentrated into a very small volume in comparison to the rest of the atom.
The Rutherford model is a model of the atom we know today.

6 0

3 years ago

Read 2 more answers

A satellite moves in a circular earth orbit that has a radius of 7.49 x 106 m. A model airplane is flying on a 24.1-m guideline

mina [271]

Answer:

Explanation:

Given

radius of satellite orbit $r_1=7.49\times 10^6 m$

And orbital velocity is given by

$v=\sqrt{\frac{GM}{r}}$

where M=mass of earth $=5.98 \times 10^{24} kg$

$G=6.67\times 10^{-11}$

$v=\sqrt{\frac{6.67\times 10^{-11}\times 5.98\times 10^{24}}{7.49\times 10^6}$

$v=7.29 \times 10^3 m/s$

centripetal acceleration is given

$a_c=\frac{v^2}{r}$

$a_c=\frac{(7.29\times 10^3)^2}{7.49\times 10^6}$

$a_c=7.095 m/s^2$

For Model airplane

$a_c=\frac{v^2}{r}$

$7.095=\frac{v^2}{24.1}$

$v=\sqrt{170.98}=13.07 m/s$

4 0

4 years ago

What happens when two minerals have different arrangements of Atoms

zaharov [31]

The overall arrangements of the atoms produce crystals

5 0

3 years ago

Devices such as seat belts and airbags are used to protect passengers from which one of Newton's Laws?

denis-greek [22]

Answer:

The first Newton's Laws explains why seat belts and airbags are so important. The law is called The Car and The Wall.

Explanation:

Seat belts and airbags are for your safety and you should always follow the law. According to Newton's first law, an object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force. Any passengers in the car will also be decelerated to rest if they are strapped to the car by seat belts.

5 0

4 years ago