Answer:
q=3.5*10^-4
Explanation:
<u>concept:</u>
The force acting on both charges is given by the coulomb law:
F=kq1q2/r^2
the centripetal force is given by:
Fc=mv^2/r
The kinetic energy is given by:
KE=1/2mv^2
<u>The tension force:</u>
<u><em>when the plane is uncharged </em></u>
T=mv^2/r
T=2(K.E)/r
T=2(50 J)/r
T=100/r
<u><em>when the plane is charged </em></u>
T+k*|q|^2/r^2=2(K.E)charged/r
100/r+k*|q|^2/r^2=2(53.5 J)/r
q=√(2r[53.5 J-50 J]/k) √= square root on whole
q=√2(2)(53.5 J-50 J)/8.99*10^9
q=3.5*10^-4
Answer:
b. 48.0 g.
Explanation:
Given;
mass of the exoplanet,
radius of the exoplanet,
The acceleration due to gravity of the planet is calculated as;
Therefore, the correct option is b. 48.0 g
I'm in middle school, but I think I know the answer, I am sorry if I am wrong.
It's D
Electrons move from the potassium atoms to the sulfur atoms.
Answer:
b) The ball is a freely falling body for the duration of its flight.
Explanation:
When an object is thrown upwards, it moves against the direction of gravity. Its velocity decreases with respect to its motion, and zero at the maximum height. After which it falls back to the surface of the earth.
Since the ball moves initially against the force of gravity, its acceleration would be -9.8 m/ at its highest point. Thus since acceleration is constant, the ball is a freely falling body for the duration of its flight.