3/5 in 30 mins, 5*30=150, then she would write 3/150 or 1/50 each minute
Answer:
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
---------------
-2x+2y+3z=0
-2x-y+z=-3
---------------- Subtract
3y + 2z = 3 Eqn A
=========================
-2x-y+z=-3
2x+3y+3z=5
---------------- Add
2y + 4z = 2
6y + 4z = 6 Eqn A times 2
------------------------------------ Subtract
-4y = -4
y = 1
-----------------
z = 0
-------------------
x = 1
Answer: {(x + 2), (x - 1), (x - 3)}
Step-by-step explanation:
Presented symbolically, we have:
x^3 - 2x^2 - 5x + 6
Synthetic division is very useful for determining roots of polynomials. Once we have roots, we can easily write the corresponding factors.
Write out possible factors of 6: {±1, ±2, ±3, ±6}
Let's determine whether or not -2 is a root. Set up synthetic division as follows:
-2 / 1 -2 -5 6
-2 8 -6
-----------------------
1 -4 3 0
since the remainder is zero, we know for sure that -2 is a root and (x + 2) is a factor of the given polynomial. The coefficients of the product of the remaining two factors are {1, -4, 3}. This trinomial factors easily into {(x -1), (x - 3)}.
Thus, the three factors of the given polynomial are {(x + 2), (x - 1), (x - 3)}
Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
