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3 years ago

13

The force of gravity depends mainly on objects _______?

2 answers:

spayn [35]3 years ago

6 0

Distance is the most important factor. Although the masses of the two objects are important, the product of their masses is then divided by the square of the distance between them.

geniusboy [140]3 years ago

5 0

The strength of the gravitational forces between two objects depends on
the masses of both objects and on the distance between their centers.

I don't think you can say that one or the other is the "<em>main</em>" influence.

-- If each mass is multiplied by ' k ', then the forces between them are
multiplied by ' k² '.

-- And if the distance between them is multiplied by ' k ', then the forces
between them are divided by ' k² '.

Seems pretty equal to me.

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Can electromagnetic waves travel in a vacuum? <br><br> Yes <br> Or<br> No

Sonja [21]

Answer:

Yes

Explanation:

Yes because Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

3 0

3 years ago

What must be the diameter of a cylindrical 120-m long metal wire if its resistance is to be 6.0 ω? the resistivity of this metal

Free_Kalibri [48]

The resistance of the cylindrical wire is $R=\frac{\rho l}{A}$ .

Here $R$ is the resistance, $l$ is the length of the wire and $A$ is the area of cross section. Since the wire is cylindrical $A=\frac{\pi d^2}{4}$ . Rearranging the above equation,

$A=\frac{\rho l}{R}\\ \frac{\pi d^2}{4}=\frac{\rho l}{R}\\ d=\sqrt{\frac{4\rho l}{\pi R}}$

Here $l=120, R=6, \rho=1.68(10^{-8})$ .

Substituting numerical values,

$d=\sqrt{\frac{4(1.68)(10^{-8}) (120)}{\pi (6)}}\\ d=0.0006541$

Te diameter of the wire is $0.6541 mm$

7 0

4 years ago

Some unpolarized light has an intensity of 1375 W/m2 before passing through three polarizing filters. The transmission axis of t

chubhunter [2.5K]

Answer:

intensity of the light that emerges from the three filters is 560.80 W/m²

Explanation:

Given data

intensity I = 1375 W/m2

angle 1 = 31.0°

angle 2 = 41.0°

to find out

intensity of the light that emerges from the three filters

solution

we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5 W/m2

so intensity after 2nd polarize pass = I 1st cos²(θ)

I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754) = 575.27 W/m2

and

intensity after 3rd polarize pass = I 2nd cos²(θ)

I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2

so that intensity of the light that emerges from the three filters is 560.80 W/m²

4 0

4 years ago

A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid

Sergeeva-Olga [200]

Answer:

$8.37*10^5$ rpm

Explanation:

Given that rotational kinetic energy = $4.66*10^9J$

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = $\frac{1}{2} mr ^2$

Rotational K.E is illustrated as $(K.E)_{rt} = \frac{1}{2} I \omega^2$

$\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }$

$\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }$

$\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }$

$\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }$

$\omega = 87636.04$

$\omega = 8.76*10^4 rad/s$

Since 1 rpm = $\frac{2 \pi}{60} rad/s$

$\omega = 8.76*10^4(\frac{60}{2 \pi})$

$\omega = 836518.38$

$\omega = 8.37 *10^5 rpm$

3 0

3 years ago

When all the forces on an object are equal and opposite, & the net force is zero, that's..

Serggg [28]

That would be a balanced force because the forces cancel each other out.

3 0

4 years ago