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Anika [276]
3 years ago
7

5. This break-dancer's speed is not changing as he spins on his head, but he is

Physics
1 answer:
n200080 [17]3 years ago
8 0

Answer:

the velocity is changing therefore the acceleration is changing too.

Explanation:

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A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 6.55x10-2 kg/s. The density of the gasoline is 740
klasskru [66]

Answer:

speed = 3.95 m/s

Explanation:

area = π x radius^2

area = π x (2.67 x 10^-3)^2

volume flow rate = area x speed

volume / time = area x speed

density = mass / volume

volume = mass / density

<u>mass / (density x time) = area *speed</u>

mass flow rate = mass / time

<u>mass flow rate / density = area x speed</u>

6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed

speed =8.8514 x 10-5 /2.2396 x 10-5 m/s

speed = 3.95 m/s

6 0
3 years ago
Earth's surface receives about twice as much energy from the atmosphere than from the sun as a result of ____.
Oxana [17]
I think the answer is “greenhouse effect”
5 0
3 years ago
An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic
malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

\omega_f = \omega_0 + \alpha t

Where,

\omega_f =Final Angular Velocity

\omega_0 =Initial Angular velocity

\alpha = Angular acceleration

t = time

The relation between the tangential acceleration is given as,

a = \alpha r

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s

\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s

t = 11s

Replacing the previous equation with our values we have,

\omega_f = \omega_0 + \alpha t

9.8436 = 6.5973 + \alpha (11)

\alpha = \frac{9.8436- 6.5973}{11}

\alpha = 0.295rad/s^2

The tangential velocity then would be,

a = \alpha r

a = (0.295)(0.2)

a = 0.059m/s^2

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

\omega_f^2=\omega_0^2+2\alpha\theta

Replacing with our values and re-arrange to find \theta,

\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}

\theta = \frac{9.8436^2-6.5973^2}{2*0.295}

\theta = 90.461rad

That is equal in revolution to

\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev

The linear displacement of the system is,

x = \theta*(2\pi*r)

x = 14.397*(2\pi*\frac{0.25}{2})

x = 11.3m

5 0
3 years ago
Which best describes electromagnetic waves moving from gamma rays to radio waves along the electromagnetic spectrum
kondor19780726 [428]

Answer:

Explanation:

No

9 0
3 years ago
The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m (2716.5 ft) and has more than 160 stories. A t
lakkis [162]

Explanation:

Below is an attachment containing the solution.

5 0
3 years ago
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