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3 years ago

5. This break-dancer's speed is not changing as he spins on his head, but he is

Physics

1 answer:

n200080 [17]3 years ago

8 0

Answer:

the velocity is changing therefore the acceleration is changing too.

Explanation:

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A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 6.55x10-2 kg/s. The density of the gasoline is 740

klasskru [66]

Answer:

speed = 3.95 m/s

Explanation:

area = π x radius^2

area = π x (2.67 x 10^-3)^2

volume flow rate = area x speed

volume / time = area x speed

density = mass / volume

volume = mass / density

<u>mass / (density x time) = area *speed</u>

mass flow rate = mass / time

<u>mass flow rate / density = area x speed</u>

6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed

speed =8.8514 x 10-5 /2.2396 x 10-5 m/s

speed = 3.95 m/s

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3 years ago

Earth's surface receives about twice as much energy from the atmosphere than from the sun as a result of ____.

Oxana [17]

I think the answer is “greenhouse effect”

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3 years ago

An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic

malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

$\omega_f = \omega_0 + \alpha t$

Where,

$\omega_f =$ Final Angular Velocity

$\omega_0 =$ Initial Angular velocity

$\alpha =$ Angular acceleration

t = time

The relation between the tangential acceleration is given as,

$a = \alpha r$

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

$\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s$

$\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s$

$t = 11s$

Replacing the previous equation with our values we have,

$\omega_f = \omega_0 + \alpha t$

$9.8436 = 6.5973 + \alpha (11)$

$\alpha = \frac{9.8436- 6.5973}{11}$

$\alpha = 0.295rad/s^2$

The tangential velocity then would be,

$a = \alpha r$

$a = (0.295)(0.2)$

$a = 0.059m/s^2$

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

$\omega_f^2=\omega_0^2+2\alpha\theta$

Replacing with our values and re-arrange to find $\theta,$

$\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}$

$\theta = \frac{9.8436^2-6.5973^2}{2*0.295}$

$\theta = 90.461rad$

That is equal in revolution to

$\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev$

The linear displacement of the system is,

$x = \theta*(2\pi*r)$

$x = 14.397*(2\pi*\frac{0.25}{2})$

$x = 11.3m$

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3 years ago

Which best describes electromagnetic waves moving from gamma rays to radio waves along the electromagnetic spectrum

kondor19780726 [428]

Answer:

Explanation:

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3 years ago

The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m (2716.5 ft) and has more than 160 stories. A t

lakkis [162]

Explanation:

Below is an attachment containing the solution.

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3 years ago