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Anika [276]
2 years ago
7

5. This break-dancer's speed is not changing as he spins on his head, but he is

Physics
1 answer:
n200080 [17]2 years ago
8 0

Answer:

the velocity is changing therefore the acceleration is changing too.

Explanation:

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wo parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude
melisa1 [442]

Answer:

<em> -18896.49 V/m</em>

<em></em>

Explanation:

Distance between the two plates = 10 cm = 10 x 10^{-2} m = 0.1 m

Also, one of the plates is taken as<em> zero volt.</em>

a. The potential strength between the zero volt plate, and 7.05 cm (0.0705 m) away is 393 V

b. The potential strength between the other plate, and 2.95 cm (0.0295 m) away is 393 V

<em>Potential field strength = -dV/dx</em>

where dV is voltage difference between these points,

dx is the difference in distance between these points

For the first case above,

potential field strength = -393/0.0705 = -5574.46 V/m

For the second case ,

potential field strength = -393/0.0295 = -13322.03 V/m

Magnitude of the field strength across the plates will be

-5574.46 + (-13322.03) = -5574.46 + 13322.03 =<em> -18896.49 V/m</em>

6 0
3 years ago
Who was the first known contributor to the atomic theory? Select one: a. Thomson b. Bohr c. Dalton d. Democritus
ser-zykov [4K]
It would be D Democritus
He contributed in around 460-370 BC
Whereas the others contributed much later from around 1700's - 1900's
6 0
3 years ago
Electronic flash units for cameras contain a capacitor for storing the energy used to produce the flash. In one such unit, the f
gladu [14]

Answer:

A) energy to be stored = 354.4J

B) capacitance = 0.0454 farad

Explanation:

Detailed explanation and calculation is shown in the image below

8 0
2 years ago
What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?
Butoxors [25]

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

E=\frac{25V}{0.05m}=500\frac{V}{m}

Hence, the electric field strength is 500V/m

5 0
1 year ago
Write a letter to your friend telling him how you are keeping active with your studies at home due to the Coronavirus Pandemic o
tangare [24]

Answer:

HERPES CURE OR ANY DISEASES CONTACT_________________________ ROBINSONBUCLER  ((G MAIL.)) COM ……………

Explanation:

7 0
3 years ago
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