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vova2212 [387]
4 years ago
9

15 POINTS

Physics
1 answer:
Vladimir [108]4 years ago
6 0

Answer:

The given equation tells the relationship between the velocity and the length of skid mark,so simply by putting the given values,we can determine the length of the skid mark.

Given,

v

=

25

miles/ hrs=

25

⋅

(

5280

3600

)

f

t

s

i.e

36.67

f

t

s

f

=

0.5

So,from the equation,we get the length of the skid mark=

d

=

36.67

√

32

⋅

0.5

i.e

12.98

f

tExplanation:

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Convection because I’m in seventh grade
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Answer:

0.06 A

Explanation:

We have given mass =0.954 kg

velocity =1.27 m/sec

efficiency =0.361 the output kinetic energy of the motor KE=\frac{1}{2}mv^2=\frac{1}{2}\times 0.954\times 1.27^2=0.769\ J

Efficiency =0.361

so input to the motor = output/efficiency

so input to the motor = \frac{0.769}{0.361}=2.1301

we know that P=\frac{E}{T} where E is energy and T is time so P=\frac{2.1301}{7.88}=0.2703W

We know that power P=VI we have given V=4.5 VOLT

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Does dispersive power of the material of a prism depends upon the shape, size and angle of prism? Explain.
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5 0
2 years ago
I need help on this physics problem.
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Answer:

the speed of the nerve impulse in miles per hour is 201.59 mi/hr

Explanation:

Given;

the speed of the nerve impulse, v = 90.1 m/s

To convert this speed in meters per second to miles per hour, we use the following method;

1,609 meter = 1 mile

3,600 s = 1 hour

v(mi/h) = 90.1 \ \frac{m}{s} \times \frac{1 \ mile}{1,609 \ m} \times \frac{3,600 \ s}{1 \ hour} = (\frac{90.1 \times 3,600}{1,609} )\frac{mi}{hr} = 201.59 \ mi/hr

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3 years ago
Protons in an accelerator at the Fermi National Laboratory near chicago are accelerated to a total energy that is 400 times thei
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(a) 0.99999687c

The relationship between total energy (E) and rest energy (E_0) is

E=\gamma E_0

where \gamma is the relativistic factor. In this problem, we know that the total energy is 400 times the rest energy: this means that

\gamma=400

The formula for the relativistic factor is

\gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}

where v is the speed of the proton and c is the speed of light. By isolating the term v/c, we find the speed of the protons in terms of c:

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(b) 3.75\cdot 10^5 MeV

Given the rest mass of a proton:

m_0=1.67\cdot 10^{-27}kg

its rest energy is the energy equivalent to this mass:

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The total energy is also sum of rest energy and kinetic energy:

E=E_0+K

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1 eV = 1.6\cdot 10^{-19} J

This kinetic energy converted into MeV (10^6 eV) is

K=\frac{6.0\cdot 10^{-8}J}{1.6\cdot 10^{-19}J/eV \cdot 10^6 eV/MeV}=3.75\cdot 10^5 MeV

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