From wave speed formula, period is 1.96 × 10^-15 seconds per cycle and the frequency is 5.1 × 10^14 Hertz
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What is Frequency ?</h3>
The frequency of a wave is the number of complete revolution per second made by a vibrating body.
Given that the wavelength of the yellow light from a sodium flame is 589 nm. This light originated from a sodium atom in the hot flame.
(a) In the sodium atom from which this light originated, the period of the simple harmonic motion which was the source of this electromagnetic wave will be found by using the formula
v = λ/T
Where
- v = speed of light = 300,000,000 m/s
- λ = wavelength = 589 × 10^-9 m
Substitute all the parameters
300000000 = 589 × 10^-9/T
T = 589 × 10^-9/300000000
T = 1.96 × 10^-15 seconds per cycle.
(b) The frequency of this light wave is the reciprocal of its period. That is,
F = 1/T
F = 1/1.96 × 10^-15
F = 5.1 × 10^14 Hertz
Therefore, the period of the wave is 1.96 × 10^-15 seconds per cycle and its frequency is 5.1 × 10^14 Hertz
Learn more about Light Wave here: brainly.com/question/10728818
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Answer:
Final Velocity = 4.9 m/s
Explanation:
We are given;. Initial velocity; u = 2 m/s
Constant Acceleration; a = 0.1 m/s²
Distance; s = 100 m
To find the final velocity(v), we will use one of Newton's equations of motion;
v² = u² + 2as
Plugging in the relevant values to give;
v² = 2² + 2(0.1 × 100)
v² = 4 + 20
v² = 24
v = √24
v = 4.9 m/s
Answer:
He is known as the first microbiologist and also “the Father of Microbiology” because he was the first to observe bacteria underneath a microscope. He made many other significant discoveries in the field of biology and also made important changes to the microscope.
Explanation:
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Answer:
i think it is 40 kilometers in the positive direction... if not im sorry
Explanation:
Answer:
For left = 0 N/C
For right = 0 N/C
At middle = 
N/C
Explanation:
Given data :-
б =
C/ m²
Considering the two thin metal plates to be non conducting sheets of charges.
Electric field is given by
1) To the left of the plate
= 0 N/C.
2) To the right of them.
= 0 N/C.
3) Between them.
= 
= 
= N/C
