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anygoal [31]
4 years ago
10

An electric hair dryer is rated 350w 110v. the safety fuse in the circuit can withstand 12a of current. how many hair dryers can

be safely operated in the circuit?
Physics
1 answer:
spayn [35]4 years ago
8 0
To determine the number of hair dryers that can be plugged in to a circuit, our basis is the maximum threshold of the current. The current which measures 12 Amperes. This current already incorporates the safety factor that is important in industrial setting.

The voltage and the current can be related to the power by the equation:

P = I*V, where I is the current in Amperes and V is the voltage in volts

Solving for the total power:

P = 12 A * 110 V
P = 1,320 Watts

Since the power rating of each hair dryer is 350 W, we divide this to the total power to determine the capacity.

Number of hair dryers = 1,320 Watts/350 Watts per hair dryer
Number of hair dryers = 3.77

In this case, we cannot round off to 4 because this would already exceed the maximum power capacity. Therefore, the total number of hair dryers allowable is 3.

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Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
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Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

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We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

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Vector A has a magnitude of 50 units and points in the positive x direction. A second vector, B , has a magnitude of 120 units a
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The x-component of a vector can be found by using the formula

v_x = v cos \theta

where

v is the magnitude of the vector

\theta is the angle between the x-axis and the direction of the vector

- Vector A has a magnitude of 50 units along the positive x-direction, so \theta_A = 0^{\circ}. So its x-component is

A_x = A cos \theta_A = (50) cos 0^{\circ}=50

- Vector B has a magnitude of 120 units and the direction is \theta_B = -70^{\circ} (negative since it is below the x-axis), so the x-component is

B_x = B cos \theta_B = (120) cos (-70^{\circ})=41

So, vector A has the greater x component.

B) Vector B

Instead, the y-component of a vector can be found by using the formula

v_y = v sin \theta

Here we have

- Vector B has a magnitude of 50 units along the positive x-direction, so \theta_A = 0^{\circ}. So its y-component is

A_y = A sin \theta_A = (50) sin 0^{\circ}=0

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where the negative sign means the direction is along negative y:

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