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3 years ago

A substance that undergoes a _____ change is still the same substance after the change. molecular chemical physical atomic

Physics

2 answers:

kirza4 [7]3 years ago

6 0

Answer:

physical change

Explanation:

anastassius [24]3 years ago

3 0

The answer is physical change

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A bird is flying in a room with a velocity field of . Calculate the temperature change that the bird feels after 9 seconds of fl

Korvikt [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The temperature change is $\frac{dT}{dt} = 1.016 ^oC/m$

Explanation:

From the question we are told that

The velocity field with which the bird is flying is $\vec V = (u, v, w)= 0.6x + 0.2t - 1.4 \ m/s$

The temperature of the room is $T(x, y, u) = 400 -0.4y -0.6z-0.2(5 - x)^2 \ ^o C$

The time considered is t = 10 \ seconds

The distance that the bird flew is x = 1 m

Given that the bird is inside the room then the temperature of the room is equal to the temperature of the bird

Generally the change in the bird temperature with time is mathematically represented as

$\frac{dT}{dt} = -0.4 \frac{dy}{dt} -0.6\frac{dz}{dt} -0.2[2 * (5-x)] [-\frac{dx}{dt} ]$

Here the negative sign in $\frac{dx}{dt}$ is because of the negative sign that is attached to x in the equation

$\frac{dT}{dt} = -0.4v_y -0.6v_z -0.2[2 * (5-x)][ -v_x]$

From the given equation of velocity field

$v_x = 0.6x$

$v_y = 0.2t$

$v_z = -1.4$

$\frac{dT}{dt} = -0.4[0.2t] -0.6[-1.4] -0.2[2 * (5-x)][ -[0.6x]]$

substituting the given values of x and t

$\frac{dT}{dt} = -0.4[0.2(10)] -0.6[-1.4] -0.2[2 * (5-1)][ -[0.61]]$

$\frac{dT}{dt} = -0.8 +0.84 + 0.976$

$\frac{dT}{dt} = 1.016 ^oC/m$

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3 years ago

How do yall like my harold

Alex777 [14]

Answer:

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3 years ago

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A power plant running at 31 % efficiency generates 270 MW of electric power. Part A At what rate (in MW) is heat energy exhauste

True [87]

Answer:

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3 years ago

Two satellites are in circular orbits around a planet that has radius 9.00×106m. One satellite has mass 68.0 kg, orbital radius

34kurt

Answer: 6782 m/s

Explanation:

Given

Radius of the planet, r = 9*10^6 m

Mass of satellite 1, m1 = 68 kg

Radius of satellite 1, r1 = 6*10^7 m

Orbital speed of satellite 1, vs1 = 4800 m/s

Mass of satellite 2, m2 = 84 kg

Radius of satellite 2, r2 = 3*10^7 m

Orbital speed of satellite 2, vs2 = ?

We know that magnitude of gravitational force, F = (G.m.m•) / r²

Where,

m = mass of satellite

m• = mass of planet

r = radius of orbit

If we consider Newton's second law that states that, F = ma, thus

F(g) = ma(rad)

Where, a(rad) = v²/r

F(g) = mv²/r

Substituting in the initial equation

mv²/r = (G.m.m•) / r²

v² = (G.m•) / r

v = √[G.m•/r]

To find vs2, we first need to find mass of the planet, m• we know that G is a gravitational constant, so we plug in the values

vs1 = √[G.m•/r1]

4800 = √[(6.67*10^-11 * m•) / 6*10^7]

4800² = (6.67*10^-11 * m•) / 6*10^7

2.3*10^7 * 6*10^7 = 6.67*10^-11 * m•

1.38*10^15 = 6.67*10^-11 * m•

m• = 1.38*10^15 / 6.67*10^-11

m• =2.07*10^25 kg

Having found that, we use the value to find our vs2

vs2 = √[(G.m•) / r2]

vs2 = √[(6.67*10^-11 * 2.07*10^25) / 3*10^7]

vs2 = √(1.38*10^15 / 3*10^7)

vs2 = √4.6*10^7

vs2 = 6782.33 m/s

Therefore, the orbital speed of the second satellite is 6782 m/s

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4 years ago

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kondor19780726 [428]

Answer:

what is the hunting age? i've never heard of it

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4 years ago

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