FIrst, just write down what we know :)
1. 1 mile = 1.6klm
2. There are 3600 seconds in an hr (<em>60s x 60mins = 3600</em>).
Now to get to <em>meters per second</em> (m/s) we need to first work out <em>meters per </em><em>hr</em> (simply convert miles to klm and then multiply by 1000)<em>.</em>
60 x 1.6 = 96 klm/hr x 1000 = 96,000 meters/hr
Now we know this, we can simply divide the meters per hr by <em>how many seconds there are in 1hr</em> to get meters per second:
96000 / 3600 = 26.67m/s
Answer:
The required power is
Explanation:
From the question we are told that
The temperature of the water entering ice machine is 
The temperature of the water leaving is 
The COP of the ice machine is 
The production rate of an ice 
The energy that needs to removed from each lbm of water at 55 F is 
Generally the cooling load of the ice machine is mathematically represented as


=> 
Generally the COP of the ice machine is mathematically represented as

Here
is the net power input needed to successfully run the ice machine
So

=> 
Converting to horsepower

=> 