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Paha777 [63]
3 years ago
10

How can we transfer a table of motion data into a line graph?

Physics
1 answer:
anastassius [24]3 years ago
4 0

Answer:

A table of motion (for a moving object) usually is something like:

Time I Position:

0s           1m

1s            3m

2s           5m

etc...

Where time is the independent variable and position represents the position of the object at that given time.

We can think in these points as coordinate pairs, for example, we can wrote these 3 pairs as:

(0s, 1m)

(1s, 3m)

(2s, 5m)

Now that we have these points, we can go to a coordinate plane and find these points

(The time would be on the horizontal axis, and position in the vertical axis)

Once you found the points, to complete the graph you need to find a line that connects the points.

An example of this is shown below, where the points used are the ones above, and the line should be straight.

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rosijanka [135]

Answer:

23.86136

Explanation:

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3 years ago
A mile is equivalent to 1.6 km. When you are driving at 60 miles per hour, what is your speed in meters per second?
yKpoI14uk [10]
FIrst, just write down what we know :)

1. 1 mile = 1.6klm
2. There are 3600 seconds in an hr (<em>60s x 60mins = 3600</em>).

Now to get to <em>meters per second</em> (m/s) we need to first work out <em>meters per </em><em>hr</em> (simply convert miles to klm and then multiply by 1000)<em>.</em>

60 x 1.6 = 96 klm/hr x 1000 = 96,000 meters/hr

Now we know this, we can simply divide the meters per hr by <em>how many seconds there are in 1hr</em> to get meters per second:

96000 / 3600 = 26.67m/s
6 0
3 years ago
Do x and y have a proportional relationship?
Alja [10]

Answer:

no they don't

Explanation:

6 0
3 years ago
A 4000kg truck has a head-on inelastic collision with a 2500kg truck.
iogann1982 [59]

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7 0
3 years ago
Water enters an ice machine at 55F and leaves as ice at 25F. If the COP of the ice machine is 3.7 during this operation, determi
boyakko [2]

Answer:

The required power is P_i = 0.2692 \ hp

Explanation:

From the question we are told that

   The temperature of the water entering ice machine is T_1 =  55 ^o F

    The temperature of the water leaving is T_2 = 25 ^oF

    The COP of the ice machine is COP= 3.7

    The production rate of an ice  \r m = 15.0 \ lbm /hr

    The energy that needs to removed from each lbm of water at 55 F is E = 169 Btu

Generally the cooling load of the ice machine is mathematically represented as

       \r Q_L =  \r m * E

      \r Q_L =15 * 169

=>  \r Q_L = 2535 \ Btu/h

Generally the COP of the ice machine is mathematically represented as

       COP =  \frac{\r Q_L}{P_i}

Here P_i is the net power  input needed to successfully run the ice machine

So  

     3.7 =  \frac{2535}{P_i}

=>   P_i = 685 \  Btu/h

Converting to horsepower

      P_i = \frac{685}{2545}

=>   P_i = 0.2692 \ hp

     

3 0
3 years ago
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