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Citrus2011 [14]
3 years ago
13

Define escape velocity ​

Physics
2 answers:
lianna [129]3 years ago
8 0

Answer:

the lowest velocity which a body must have in order to escape the gravitational attraction of a particular planet or other object.

Explanation:

Nana76 [90]3 years ago
5 0

Answer:

minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a massive body.

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If an object's kinetic energy is zero, what is its momentum?
hammer [34]
If the object's kinetic energy is zero, then due to in multiplication factor, it's momentum will also be equal to zero 'cause the velocity of the object must be Nil

In short, Your Answer would be: "Zero"

Hope this helps!
6 0
3 years ago
In 4 -5 sentences, summarize the science of the sport of curling and how it relates to friction
zalisa [80]
Well, a curler uses heat to calm down friction so I am not sure
5 0
3 years ago
As an airplane accelerates in level flight, what parameter must the pilot adjust to keep level and balance Lift = Weight?
Y_Kistochka [10]

Answer:

C. Angle of Attack.

Explanation:

The pilot must adjust the angle of attack parameter. The angle of attack of this plane to get to the desired lift coefficient.

And thus, we have

Lift = Weight

3 0
2 years ago
Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of
natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

r'=4.12\ m

We need to calculate the path difference

Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

\lambda=1.143\ m

We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

7 0
3 years ago
Why does the moon exert a greater tidal influence than the sun?
andreyandreev [35.5K]
Well, I'm not sure right now that it actually does.

But if it does, that's because the sun is about 400 times
FARTHER from the Earth than the moon is.
4 0
3 years ago
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