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Citrus2011 [14]
3 years ago
13

Define escape velocity ​

Physics
2 answers:
lianna [129]3 years ago
8 0

Answer:

the lowest velocity which a body must have in order to escape the gravitational attraction of a particular planet or other object.

Explanation:

Nana76 [90]3 years ago
5 0

Answer:

minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a massive body.

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the electrons shared between the oxygen and hydrogen atoms spend more time around the oxygen atom nucleus than around the hydrogen atom nucleus

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3 years ago
A bus starts from rest.if the acceleration is 2m/s square, find
MrMuchimi

Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

3 0
2 years ago
A residential subdivision encompasses 1100 acres with a housing density of four houses per acre. Assume that a high-value reside
aleksandrvk [35]

Answer:

(a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

Explanation:

Given that,

Area = 1100 acres

Number of house in 1 acres = 4

\text{Number of house in 1100 acres} = 4\times1100

\text{Number of house in 1100 acres} = 4400

Per house water demand = 800 g/day/house

(a). We need to calculate the average daily demand of this subdivision

Using formula for average daily demand

\text{average daily demand}=house\times\text{Per house water demand}

\text{average daily demand}=4400\times800\ gallon/day

\text{average daily demand}=3520000\ gallon/day

\text{average daily demand}=\dfrac{3520000}{24\times60}\ gallon/min

\text{average daily demand}=2444.44\ gallon/min

The average daily demand of this subdivision is 2444.44 gallon/min.

(b). We need to calculate the design-demand used to design the distribution system

Using formula for the design-demand

\text{design demand}=(Q_{max})daily\times\text{fire flow}

\text{design demand}=1.64\times2444.4\times1000

\text{design demand}=4008816\ gallon/m

Hence, (a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

8 0
3 years ago
The clownfish is classified as an omnivore because it eats
vodka [1.7K]
Because it eats plants and animals. 
3 0
3 years ago
A solution that contains a small amount of salt and a large amount of water is said to be a _______ solution.
GrogVix [38]
It's a dilute solution
3 0
3 years ago
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