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3 years ago

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1. Rewrite using standard notation: 54.1 x 10^-3 /// 2. Rewrite using standard notation : 291.2 x 10^-2 ///3. in this expression

, what number is the coefficient ? 4.12 x 10^-3

1 answer:

valkas [14]3 years ago

8 0

<span>(291.2 x 10^-2)/3 technically that is standard notation
the answer solved is </span><span>0.304

</span>

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I can't figure out how to do (i + j) x (i x j)for vector calc

Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

$\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}$

Then, solving the determinant

$\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}$

In our case,

$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

Where we used the formula for AxB to calculate ixj.

Finally,

$\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}$

Thus, (i+j)x(ixj)=i-j

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1 year ago

How are fractions divided the right way?

Lady_Fox [76]

You would keep the first fraction the same , turn the division sign into a multiplication sign , and flip the 2nd fraction upside down.

10/14 ÷ 7/16

10/14 x 16/7= 80/49 = 1 31/49

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3 years ago

If x+9.8=14.7, what is the value of 8(x-3.7?

yulyashka [42]

First find X by subtracting 9.8 from 14.7
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than fill in the equation for x
8(4.9-3.7)
you then subtract in the parenthasis
getting the answer of 1.2
finally multiply 1.2x8
Your final answer is 9.6

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3 years ago

Line segment AB has endpoints A(1, 4) and B(2, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has en

kumpel [21]

To determine the scale factor of the dilation, we determine the distances between the endpoints of the two lines through the equation,
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3 years ago

Read 2 more answers

Lcm of 3x^(2) and 10

Ahat [919]

Answer:

the least common multiple is 18

Step-by-step explanation:

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3 years ago