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faust18 [17]
3 years ago
15

Common effects of cocaine include

Chemistry
1 answer:
viktelen [127]3 years ago
7 0
Constricted blood vessels
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A copper atom has a mass of 1 06 times 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the questions be
amm1812

Answer:

Mass of 1 mole of copper is 63.83 g.

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

Explanation:

Mass of 1 copper atom,m = 1.06\times 10^{-22} g

1 mole = 6.022\times 10^{23} atoms

Mass of 1 mole of copper :

= 6.022\times 10^{23} atoms\times 1.06\times 10^{-22} g=63.83 g

Mass of 1 mole of copper = 63.83 g

Mass of copper penny = 2.5 g

Atomic mass of copper = 63.83 g/mol

Moles of copper in 2.5 g of copper penny:

\frac{2.5 g}{63.83 g/mol}=0.03916 mol

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

8 0
3 years ago
Someone pls help me I will make you brain
wlad13 [49]

Answer:

It is true answer. Ozone = O3

7 0
3 years ago
In a Lewis diagram for methane (CH4), which atom or atoms is inside, or central?
Ahat [919]

Answer:

B carbon

Explanation

Lewis structure or dot structure is an easy way to get the bonding details of atoms in a molecule. If we talk about methane molecule carbon is central atom with four electrons that are bonded to four hydrogen atoms and each bond is single covalent bond.

Please see attached figure,

Hope it helps!

7 0
2 years ago
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Lead will float in water.
Fed [463]

Actually, no. While their mass may be the same (1kg), the volume of lead is a lot smaller than that of feathers. As there is the same mass stuffed in a smaller space, it must be denser. The density of water is 1 g/cm3, so if the density of the lead is more than 1g/cm3, it has to sink

7 0
3 years ago
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Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
2 years ago
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