<span>0.40008 L is the correct answer.</span>
Answer:
30.06904
Explanation:
C3H4: Mass % C = 36.033 x 100 / 40.0641 = 89
Answer:
The answer is D. None of the light is refracted or reflected.
Explanation:
Just trust :)
Answer:
CH₃CH₂CH₂COOH > CH₃CH₂COOH > ClCH₂CH₂COOH > ClCH₂COOH
Explanation:
Electron-withdrawing groups (EWGs) increase acidity by inductive removal of electrons from the carboxyl group.
Electron-donating groups (EDGs) decrease acidity by inductive donation of electrons to the carboxyl group.
- The closer the substituent is to the carboxyl group, the greater is its effect.
- The more substituents, the greater the effect.
- The effect tails off rapidly and is almost zero after about three C-C bonds.
CH₃CH₂-CH₂COOH — EDG — weakest — pKₐ = 4.82
CH₃-CH₂COOH — reference — pKₐ = 4.75
ClCH₂-CH₂COOH — EWG on β-carbon— stronger — pKₐ = 4.00
ClCH₂COOH — EWG on α-carbon — strongest — pKₐ = 2.87
Answer: 41.2 grams will remain undissolved
Explanation: The solubility for the salt is 360 g/liter, or 0.36 g/ml. (Based on the word "around" which I take as the limit of solubility).
Thus, if we have 580 ml, (0.36g/ml)*(580ml) = 208.8 grams dissolve.
(250g - 208.8g) = 41.2 grams undissolved.