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Sergeeva-Olga [200]
4 years ago
12

Select the correct answer. A certain reaction has this form: aA bB. At a particular temperature and [A]0 = 2.00 x 10-2 Molar, co

ncentration versus time data were collected for this reaction and a plot of ln[A]t versus time resulted in a straight line with a slope value of -2.97 x 10-2 min-1. What is the half-life of this reaction? A. 23.33 seconds B. 0.043 minutes C. 0.0043 seconds D. 23.33 minutes E. 1680 minutes
Chemistry
1 answer:
Pie4 years ago
7 0

Answer:

\large \boxed{\text{D. 23.34 min}}

Explanation:

1. Find the order of reaction

Use information from the graph to find the order.

If a plot of ln[A] vs time is linear, the reaction is first order and the slope = -k.

2. Find the  half-life

k = \dfrac{\ln2}{ t_{\frac{1}{2}}}\\\\k = \text{-slope} = -(-2.97 \times 10^{-2} \text{ min}^{-1}) =2.97 \times 10^{-2} \text{ min}^{-1} \\ t_{\frac{1}{2}} =\dfrac{\ln 2}{k} = \dfrac{\ln 2}{2.97 \times 10^{-2}\text{ min}^{-1}} =\textbf{23.34 min}\\\\\text{The half-life is $\large \boxed{\textbf{23.34 min}}$}

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The balanced nuclear equation for the reaction is

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From the question given above, we were told that:

<u>A fast-moving neutron strikes a ²³⁵U nucleus. The nucleus shatters producing ¹⁵⁵Sm, ⁷⁸Zn, and three neutrons.</u>

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<h3>²³⁵₉₂U + ¹₀n —> ¹⁵⁵₆₂Sm +  ⁷⁸₃₀Zn + 3(¹₀n)</h3>

 

 The nuclear equation above is balanced.

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