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makvit [3.9K]
3 years ago
10

In a Lewis diagram for methane (CH4), which atom or atoms is inside, or central?

Chemistry
2 answers:
Ahat [919]3 years ago
7 0

Answer:

B carbon

Explanation

Lewis structure or dot structure is an easy way to get the bonding details of atoms in a molecule. If we talk about methane molecule carbon is central atom with four electrons that are bonded to four hydrogen atoms and each bond is single covalent bond.

Please see attached figure,

Hope it helps!

Marat540 [252]3 years ago
5 0

Answer:

B) carbon

Explanation:

A Lewis structure depicts the distribution of valence electrons around the atom. Since it is the valence electrons that are involved in the formation of chemical bonds, Lewis structures are therefore an import tools for visualizing molecular geometries.

In the given molecule methane, CH₄:

the valence configuration for C = 2s²2p²

the valence configuration for H = 1s¹

Since two electrons are required to form a bond, the C atom in methane can form one bond with each of the 4 H atoms. Therefore, in the Lewis diagram, the C atom will be in the center surrounded by the 4 H atoms.

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Changes into new substances called product.
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Of the molecules below, only ________ is polar.a. SiCl4 b. CH4 c. CCl4 d. SeF4
ludmilkaskok [199]

Answer:

SeF4 is a polar molecule

Explanation:

SeF4 is a polar molecule because a polar molecule is any molecule that have lone pairs of electrons in the central atom or have atoms that are electronegative and the electrons between that are covalently bonded are not evenly distributed.

The electronegative atoms of flourine in SeF4 are not evenly distributed and kind pairs of electrons are on the central atom.

6 0
3 years ago
Which of the following elements has the largest electronegativity? A) Bismuth B) Nitrogen C) Potassium D) Arsenic​
algol [13]
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The answer is B) Nitrogen, which has an electronegativity of 3.04

Hope this helps!
6 0
3 years ago
Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3
Semmy [17]

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

6 0
3 years ago
19.3 g of cadmium hydroxide reacted with 15.21 g of hydrobromic acid. How many grams of water can be made?
Alecsey [184]

Answer:

m_{H_2O}=3.384gH_2O

Explanation:

Hello,

In this case, the chemical reaction is:

Cd(OH)_2+2HBr\rightarrow CdBr_2+2H_2O

Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:

n_{H_2O}^{by\ Cd(OH)_2}=19.3gCd(OH)_2*\frac{1molCd(OH)_2}{146.4gCd(OH)_2}*\frac{2molH_2O}{1molCd(OH)_2}=0.264molH_2O\\\\n_{H_2O}^{by\ HBr}=15.21gHBr*\frac{1molHBr}{80.9gHBr}*\frac{2molH_2O}{2molHBr}=0.188molH_2O

In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:

m_{H_2O}=0.188molH_2O*\frac{18gH_2O}{1molH_2O}\\ \\m_{H_2O}=3.384gH_2O

Regards.

4 0
3 years ago
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