Ask question

Ask question

All categories

3 years ago

13

63. The magnetic force acting on a moving charge is given by the product of three quantities,

1 answer:

ki77a [65]3 years ago

3 0

Answer:

the correct one is 3

Explanation:

The magnetic force is described by the expression

F = q v x B

The bold indicate vectors, q is the charge, v the velocity and B the magnetic induction

This expression can be written in scalar form

F = q v B sin θ

where θ is the angle between velocity and induction.

The direction of the force is perpendicular to the vectors.

When revising this expression the force depends on the electric charge, the speed of the particle and the induction of the magnetic field

therefore, checking the possible answers, the correct one is 3

You might be interested in

Al enfriar una placa cuadrada metálica de 8 cm de longitud su lado disminuye un 0.03%

Xelga [282]

Acceptame para ser amigos y luego te ayudo

3 0

4 years ago

A capacitor of 30.0 μ F 30.0 μF and a resistor of 110 Ω 110 Ω are quickly connected in series to a battery of 4.00 V. 4.00 V. Wh

Tanzania [10]

Answer: $Q=31.368\ \mu C$

Explanation:

Given

capacitance $C=30\ muF$

Resistance $R=110\ Omega$

Applied Voltage $V=4\ V$

$t=0.001\ s$

Charge on Capacitor in a R-C circuit is given by

$Q=Q_0(1-e^{\frac{-t}{RC}})$

$Q=CV(1-e^{\frac{-t}{RC}})$

$Q=30\times 10^{-6}\times 4(1-e^{\frac{-0.001}{110\times 30\times 10^{-6}}})$

$Q=120\times 10^{-6}\times 0.2614$

$Q=31.368\ \mu C$

8 0

4 years ago

It’s your birthday, and to celebrate you’re going to make your first bungee jump. You stand on a bridge 100 m above a raging riv

amm1812

Answer:

$X'=50.4\,m$

Explanation:

Given that:

Height of jump, $h=100\,m$

length of elastic cord, $l=30\,m$

spring constant of the cord, $k=40\,N.m^{-1}$

mass of the body that jumps, $m=80\,kg$

Force on the bungee elastic cord:

$F=m.g$

$F=80\times 9.8$

Now this force F will be responsible for the elongation in the elastic cord, so:

$F=k.x$ ............................(1)

where :

k = spring constant

x = extension in the elastic cord

using eq. (1)

$80\times 9.8=40\times x$

$x=19.6\,m$

So the cord stretches 19.6 meters more beyond its original length of 30 meters.

Hence, the remaining distance from the river surface at the bottom is:

$X'=100-(30+19.6)$

$X'=50.4\,m$

3 0

3 years ago

A 104.328-kg baserunner slides into home base. He starts his slide moving at 8.451 m/s and 6.596 m from home base; when he cross

JulijaS [17]

The coefficient of kinetic friction between the baserunner and the ground is 0.51.

<h3>Coefficient of kinetic friction </h3>

The coefficient of kinetic friction between the base runner and the ground is calculated as follows;

μ = a/g

where;

a is acceleration
g is gravity

v² = u² + 2as

a = (v² - u²)/(2s)

a = (8.451² - 2.322²)/(2 x 6.596)

a = 5 m/s²

μ = 5/9.8

μ = 0.51

Thus, the coefficient of kinetic friction between the baserunner and the ground is 0.51.

Learn more about coefficient of friction here: brainly.com/question/14121363

#SPJ1

7 0

2 years ago

If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite directi

Naya [18.7K]

Answer:

The magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $97.5 m$

Explanation:

Given:

Velocity of a pitched ball $v _{i} = 47$ $\frac{m}{s}$

Velocity of ball after impact $v_{f} = -50.5$ $\frac{m}{s}$

From the formula of change in momentum,

$\Delta P = m (v_{f} -v_{i} )$

Here mass is not given in question,

Mass of ball is $m$

Change in momentum is given by,

$\Delta P = m (-50.5 -47)$

$\Delta P = -97.5 m$

Magnitude of change in momentum is

$\Delta P = 97.5 m$

And impulse is given by

$J = \Delta P$

$J = -97.5 m$

So impulse and

Therefore, the magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $-97.5 m$

6 0

3 years ago