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Sedbober [7]
3 years ago
7

When sodium and chlorine combine to form sodium

Physics
2 answers:
lyudmila [28]3 years ago
4 0

Answer:

product

Explanation: it's the product of chlorine and sodium

lina2011 [118]3 years ago
3 0

Answer:

y

Explanation:

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Sam and George are riding in separate cars on the freeway. The lanes they are driving in are adjacent. We choose our coordinate
butalik [34]

Answer:

(a) Relative speed of Sam = -7 mph

(b) Relative speed of George = 7 mph

Explanation:

We have given speed of Sam 65 mph in north direction.

And speed of George is 72 mph also in north direction

We have find the relative velocity of both Sam and George

(a) Speed of Sam relative to George = speed of Sam - speed of George = 65 -72 = -7 mph

(b) Speed of George with respect to Sam = speed of George - speed of Sam = 72-65 = 7 mph

3 0
3 years ago
PLEASE HELP!
lana66690 [7]

Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

(m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

(2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]

Now using the following equation of kinematics, we can determine the distance traveled.

v_{2}^{2} =v_{1}^{2}+2*a*x

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]

8 0
3 years ago
How to find the period of a wave
____ [38]
The method to choose depends on what information you have, and
on what you can measure.  Here are a few possible methods:

-- Measure the period. Start your clock when one peak
of the wave passes you.  Stop the clock when the next
peak passes you.  The time between the two peaks is
the wave's period.

-- Divide the wave's wavelength by its speed.  That quotient
is the wave's period.

-- Use an electronic frequency meter to measure the wave's
frequency.  Then take its reciprocal (divide ' 1 ' by it).  The
result is the wave's period.
5 0
4 years ago
A particle on the x-axis is moving to the right at 2 units per second. At a certain instant it is at the point (5,0). How rapidl
koban [17]

Answer:

dr/dt = 1.94 units per second

Explanation:

A particle is moving on the x-axis to the right at 2 u/s.

To know how is changing the distance of the particle respect to the point (0,9), on the y-axis, you first take into account that the distance between charge and a point over the y-axis is given by:

r^2=x^2+y^2          (1)

Next, you calculate implicitly the derivative of the equation (1) respect to t:

\frac{d}{dt}r^2=\frac{d}{dt}[x^2+y^2]\\\\2r\frac{dr}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}       (2)

Next, you solve the previous equation for dr/dx:

\frac{dr}{dt}=\frac{x(dx/dt)+y(dy/dt)}{\sqrt{x^2+y^2}}       (3)

dx/dt: the speed of the particle on the x-axis = 2

dy/dt: speed of the particle on the y-axis = 0

For the instant given in the statement, you have that:

x = 5

y = 9

Then, you replace the values for x, y, dx/dt and dy/dt in the equation (3):

\frac{dr}{dt}=\frac{2(5)(2)+0}{\sqrt{(5)^2+(9)^2}}=1.94

The speed of change of the distance between particle and point (0,9) is 1.94 units per second

6 0
3 years ago
A force of 1000 n is exerted on a golf ball for 0.005 s . The Change In momentum of the golf ball is
liubo4ka [24]

Answer:

5

Explanation:

Change in momentum equal to mass times time.

3 0
4 years ago
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