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castortr0y [4]
3 years ago
6

What is the new volume of a gas at standard pressure (760 mm Hg) if originally 2.30 L of the gas had a pressure of 725.0 mmHg?

Chemistry
1 answer:
maksim [4K]3 years ago
7 0

Answer:

2.19L

Explanation:

Information from the question include:

V1 (initial volume) = 2.3L

P1 (initial pressure) = 725mmHg

P2 (final pressure) = 760mmHg

V2 (final volume) =?

With the Boyle's law equation P1V1 = P2V2, the final volume can easily be obtain as follow:

P1V1 = P2V2

725 x 2.3 = 760 x V2

Divide both side by 760

V2 = (725 x 2.3)/760

V2 = 2.19L

Therefore, the new volume of the gas at standard pressure is 2.19L

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Answer:

the pressure exerted in pascals is 0.5 Pa

Explanation:

The computation of the pressure exerted in pascals is shown below:

As we know that

Pressure = force ÷ area

= 25 ÷ 50

= 0.5 Pa

Hence, the pressure exerted in pascals is 0.5 Pa

We simply applied the above formula so that the correct pressure could come

4 0
3 years ago
What is the definition of the word: Property (the scientific definition A makes up matter; makes up the world around us B an obj
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Answer:

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Calculate the molar mass of NH4NO3. Molar mass of NH4NO3 = g/mol.
bija089 [108]

The molar mass of NH4NO3 in g/mol is 80g/mol.

HOW TO CALCULATE MOLAR MASS:

The molar mass of a compound can be calculated by summing the atomic masses of its constituent elements.

In ammonium nitrate (NH4NO3), there are nitrogen, hydrogen, and oxygen elements.

  • Atomic mass of nitrogen = 14
  • Atomic mass of oxygen = 16
  • Atomic mass of hydrogen = 1

Molar mass of NH4NO3 = 14 + 1(4) + 14 + 16(3)

Molar mass of NH4NO3 = 80g/mol

  • Therefore, the molar mass of NH4NO3 in g/mol is 80g/mol.

Learn more about molar mass at: brainly.com/question/8101390?referrer=searchResults

4 0
3 years ago
Read 2 more answers
4 NH3 + 6 NO → 5 N2 + 6 H2O How many moles of NH3 are necessary to produce 0.824 mol N2?
GrogVix [38]
4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂

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6 0
4 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

7 0
3 years ago
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