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harkovskaia [24]
4 years ago
15

How are atoms arranged in mixtures? 50 points

Chemistry
1 answer:
Vedmedyk [2.9K]4 years ago
6 0
There are randomly present acc. to the substance but NVR react with each other
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Calculate the % yield if the amount of alum obtained was 18.28 g and the expected amount was 19.93 g.
aliya0001 [1]

Answer:

Me too

Explanation:

I dont know why but me too

8 0
4 years ago
Read 2 more answers
What type of change occurs when rust on a nail a. chemical change b. physical change
Korvikt [17]

Answer:

Chemical change

Explanation:

The rusting of iron/a nail is a chemical change

Iron (Fe) and Oxygen (O) combine to create the compound Iron Oxide (Fe2O3), which is rust.

5 0
3 years ago
Begin by writing formulas for the reactants and products, including physical states. When necessary use coefficients to balance
xz_007 [3.2K]

Answer:

NaH(s) + H2O(l) ------> NaOH(aq) + H2(g)

2Al(s) + 3Cl2(g) -----> 2AlCl3(s)

Explanation:

The rule of thumb in balancing chemical reaction equation is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same element on the product side. Only then can any reaction equation be seen as balanced.

For example there are two aluminum atoms on both sides of the reaction equation and six chlorine atoms on both sides of the reaction equation. Hence the reaction equation is balanced.

7 0
3 years ago
Write a full set of quantum numbers for the following:
Troyanec [42]

Explanation:

It is known that the maximum value of ml is equal to the vale of l. But the minimum value of n is as follows.

                    n = l + 1

where,     n = principle quantum number  

                l = azimuthal quantum number

Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l is 0 for s, 1 for p, 2 for d, 3 for f, and so on.

Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.

  • Electronic configuration of Li is 1s^{2}2s^{1}. So here, n = 2, l = 0, m = 0 and s = ± \frac{1}{2}.
  • Electronic configuration of Br^{-} is [Ar]3d^{10}4s^{2}4p^{6}
. So here, n = 4, l = 1, m = -1, 0, +1, and s = ± \frac{1}{2}.
  • Electronic configuration of Cs^{+} is [Kr]4d^{10}5s^{2}5p^{6}. So here, n = 5, l = 1, m =  -1, 0, +1, and s = ± \frac{1}{2}.
  • Electronic configuration of B is 1s^{2}2s^{2}2p^{1}. So here, n = 2, l = 1, m = -1, 0, +1, and s = ± \frac{1}{2}.
5 0
3 years ago
How many mL of 0.100 M NaCl would be required to make a 0.0365 M solution of NaCl when diluted to 150.0 mL with water?
Tatiana [17]

Answer:

54.75 mL

Explanation:

First calculate the number of moles of NaCl in the 150mL solution of NaCl

0.0365 moles should be present on 1000cm3 or 1dm3 of water.

1L = 1 dm3

1 mL = 1 / 1000 dm3

150 mL = 150/1000 dm3 = 0.15 dm3

If x moles are present in 0.15 dm3,

x/ 0.15 = 0.0365

We get x= 0.0365 × 0.15 mol

Now x amount of moles should be taken from the initial 0.100 M NaCl solution

So 0.1 moldm-3 = 0.0365× 0.15 mol / V

we get V = 0.05475 dm3

V= 0.05475 L

V= 54.75 mL

3 0
3 years ago
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