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max2010maxim [7]
4 years ago
8

Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on co

llisions?
The change in momentum needed to stop the gymnast is increased.
The change in momentum needed to stop the gymnast is decreased.
The force exerted by the floor on the gymnast decreases.
The force exerted by the floor on the gymnast increases.
Chemistry
1 answer:
Nina [5.8K]4 years ago
8 0
I think that the answer is (D)... I hope this helped

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Answer:

The element is CARBON

The number 6 refers to the ATOMIC NUMBER

the numbers 12, 13, and 14 refer to the ATOMIC MASS

how many protons and neutrons are in the first isotope?

<u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u>6</u>

how many protons and neutrons are in the second isotope?

<u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>7</u>

<u>how many protons and neutrons are in the </u><u>t</u><u>h</u><u>i</u><u>r</u><u>d</u><u> </u><u>isotope?</u>

<u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>8</u>

<u>y</u><u>o</u><u>u</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>w</u><u>e</u><u>l</u><u>c</u><u>o</u><u>m</u><u>e</u><u> </u><u>:</u><u>)</u>

8 0
3 years ago
Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine
Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound  

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0
3 years ago
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