Mg(ClO3)2 + 2NaOH → Mg(OH)2 + 2NaClO3.
This is about as hard a question as you can get in beginning chemistry. You have to figure out which chemical between the two reactants is the LEAST number of moles before you can do anything about the products. Read that sentence over again carefully and keep in mind what least means. It's the key to the entire question.
For every mole of Mg(ClO3)2 you need two moles of NaOH. That's what the balanced equation tells you. The big number on the left of the chemical is where I'm getting 1 to 2. One is in front of Mg(ClO3)2 and 2 is to the left of NaOH
So you have 2.72 moles of Mg(ClO3)2. You would need to have 2.72*2 moles of NaOH which is 5.44 moles of NaOH. Do you have enough NaOH. (I should hear a resounding NO.) So the limiting reactant is NaOH. You only have 3.14 moles of NaOH. Now you can start getting the answer to the question
You now need to set up the same ratio for the Mg(OH)2
For every 2 moles of NaOH you get 1 mole of Mg(OH)2. The proportion is
NaOH/Mg(OH)2 = 2/1
NaOH = 3.14 moles
3.14 / Mg(OH)2 = 2/1 Cross multiply
3.14 = 2 * Mg(OH)2 Divide by 2
3.14/2 = Mg(OH)2 Combine the left
1.57 = Mg(OH)2 Answer
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I'll let you work through the second blank. I'm not completely heartless so I'll tell you that the ratio is 1:1 and that the answer should be 3.14
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Answer Box one = 1.57
Answer Box Two = 3.14
it's 3 dollars per 12 eggs so 3/12
simplify 3/12 by dividing both numbers by 3 so you get 1/4
you should know what 1/4 of a dollar is
or think of it this way 12 eggs are 3 dollars so every 4 eggs is one dollar. divide 1 dollar by 4 eggs
Here we have to get the height of the column in meter, filled with liquid benzene which exerting pressure of 0.790 atm.
The height of the column will be 0.928 m.
We know the relation between pressure and height of a liquid placed in a column is: pressure (P) = Height (h) × density of the liquid (ρ) × gravitational constant (g).
Here the pressure (P) is 0.790 atm,
or [0.790 × (1.013 × 10⁶)] dyne/cm². [As 1 atm is equivalent to 1.013 × 10⁶ dyne/cm²]
Or, 8.002ₓ10⁵ dyne/cm².
density of benzene is given 0.879 g/cm³.
And gravitational constant (g) is 980 cm/sec².
On plugging the values we get:
8.002×10⁵ = h × 0.879 × 980
Or, h = 928.931 cm
Or, h = 9.28 m (As 1 m = 100 cm)
Thus the height will be 9.28 m.
