The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.
The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an
individual gas in a mixture and n is total moles of the gas mixture. We
know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in
total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate
the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole
fraction of gas Y (x) and the total pressure (P) to calculate the
partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =
2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =
1.6 atm.
The freezing point would be 3.72 *C
Answer:
P = 3.23 atm
Explanation:
Given data:
Number of moles of gas = 30 mol
Temperature = 120°C
Volume of gas = 300 L
Pressure of gas = ?
Solution:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
120+273.15 = 393.15 K
P × 300 L = 30 mol × 0.0821 atm.L/mol.K × 393.15 K
P = 968.33 atm. L /300 L
P = 3.23 atm
I think it’s 1 Carbon, 4 hydrogens.
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