Answer:
hunting for other animals or when they are really hungry
Explanation:
From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.
Na2CO3 = 2Na+ + CO3^2-
7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
Answer:
Volume of bacteria cell into Pico liters = 60.27 Pico liters
Explanation:
Given:
Volume of bacteria cell = 6.027 x 10⁻¹⁰ L
Find:
Volume of bacteria cell into Pico liters
Computation:
1 L = 10¹² Pico liters
So,
Volume of bacteria cell = 6.027 x 10⁻¹⁰ L
Volume of bacteria cell = 6.027 x 10⁻¹⁰ x 10¹² Pico liters
Volume of bacteria cell into Pico liters = 60.27 Pico liters
Answer:
0.92% NaCl
Explanation:
To find the weight percent (aka. mass percent), you need to use the following equation:
mass of solute (g)
Mass Percent = --------------------------------- x 100%
mass of solvent (g)
In this case, NaCl is the solute and water is the solvent. You can plug the given values into the equation and solve for the mass percent.
4.6 g NaCl
Mass Percent = ------------------------ x 100%
500 g H₂O
Mass Percent = 0.0092 x 100%
Mass Percent = 0.92%