Answer:
The answer to your question is: V = 60.3 ml
Explanation:
Data
V1 = 500 ml
T1 = 27°C = 300°K
P1 = 75 mmHg = 0.098 atm
V2 = ?
T2 = - 33°C = 240°K
P2 = 0.65 atm
Formula




V2 = 60.3 ml
Answer:
V = 210.5 mL
Explanation:
∴ C1 = 0.95
∴ C2 = 0.40
∴ V2 = 0.500 L
⇒ V1 = ((0.50)(0.40))/(0.95)
⇒ V1 = 0.2105 L
Answer:
XCl2(aq) + 2 AgNO3(aq) = 2 AgCl(s) + X(NO3)2(aq)
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