Answer:
the mass number is 40 g/mole
Answer:
look at the picture
Explanation:
There are total 118 elements, out of which 92 are found in nature while the remaining have been artificially prepared. These elements are divided into metals, non-metals and metalloids depending upon their properties.
Answer:
Explanation:
Hi there,
To get started, let's first observe our rate law:
we typically use square brackets [x] for chemistry kinetics, because they specifically tell us we are dealing with <em>concentrations</em>.
This rate law is in fourth-order, because the concentrations powers add up to 4. We are not told the unit of time for this prompt (unless you know it), so I just assumed the time unit to be "time."
To calculate the reaction rate, we simply plug in the concentration of A and B into the rate law. k is the <em>rate constant</em> and stays the same for an individual reaction.
![R=(0.1 \ M^{-3}*time^{-1})[1 \ M]^2[2 \ M]^2=0.4 \ M/time](https://tex.z-dn.net/?f=R%3D%280.1%20%5C%20M%5E%7B-3%7D%2Atime%5E%7B-1%7D%29%5B1%20%5C%20M%5D%5E2%5B2%20%5C%20M%5D%5E2%3D0.4%20%5C%20M%2Ftime)
Thus, the rate of reaction with those concentrations is 0.4 M/time.
Notice, the rate constant does in fact have units of it own. The unit for k can be calculated by knowing that:
- Rate (R) must end up with units of concentration (M) per time.
- The concentrations raised to a power can be used to help solve for the units of k.
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<h3><u>Answer;</u></h3>
EtO-PHE-NH2 + H+ _______ EtO-PHE-NH3+ Cl-
<h3><u>Explanation;</u></h3>
- <em><u>p-phenetidine is p-ethoxy aniline so the amino group acts as a base. The free electron pair on nitrogen will form a coordinate covalent bond with the H+ from the ionized HCl. </u></em>
- HCl is used for the acid-base reaction in p-phenetidine in amide synthesis of acetophenetidin rather than water becuase HCl's polarity contributes to a reaction driven to the right. It protonates the amine group, making it easy to dissolve.
Answer:
8 electrons
Explanation:
as the the 1st period (H and He), it can hold up to 2 electrons. in the 2nd period (Li, Be, B, C, N, O, F and Ne), it can hold up to 8 electrons. Itstops at 6 when it reached O. add the lelectrons that you have
2+6=8
8 electrons