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3 years ago

When does boiling occur?

Chemistry

1 answer:

butalik [34]3 years ago

8 0

Water boils at 100 Degrees Celsius or 212 degrees Fahrenheit

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¿que ocurre con el electrón de Valencia del K+ en el compuesto bromuro de potasio KBr

arlik [135]

I don’t understandbddss

6 0

3 years ago

Help Tell me the answer.

Paladinen [302]

Answer:

it's easy u just have to put them in a calculator the way they are it will give you your answer atleast I think so hope this helps

5 0

2 years ago

What part of the atom is responsible for the behavior of the alpha particles?

ivann1987 [24]

Answer:

nucleus

Alpha particles are subatomic fragments consisting of two neutrons and two protons. Alpha radiation occurs when the nucleus of an atom becomes unstable (the ratio of neutrons to protons is too low) and alpha particles are emitted to restore balance.

Explanation:

8 0

3 years ago

Briefly describe the action of hardwater with soap

morpeh [17]

Answer:

The correct answer is - hard water reacts to form the calcium or magnesium salt of the organic acid of the soap.

Explanation:

Soaps are made up of fatty acids or oils by treating with strong alkali and are salts of sodium and potassium. Hard water, on the other hand, has a high concentration of minerals in comparison to soft water. When hard water and soap are mixed together the salts of the minerals like Ca2+ and Mg2+ ions present in hard water react with fatty acids of the soap.

The sodium salts are changed to the salts of calcium and magnesium which are precipitated to an insoluble substance. The insoluble salts of the calcium or magnesium dirt stick on the clothes thus cleaning ability of soap is reduced.

4 0

2 years ago

When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC = C = 0,50 J/gºC

8 0

3 years ago