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Paraphin [41]
2 years ago
5

Which is the least likely to be reduced?

Chemistry
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0

Answer:

The correct answer would actually be B

Explanation:

A P E X

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Plants perform photosynthesis
Marianna [84]
The correct answer is the fourth option. Plants perform photosynthesis during the day.<span> </span><span>Photosynthesis is the process in plants to make their food. This involves the use carbon dioxide to react with water and make sugar or glucose as the main product and oxygen as a by-product.</span>

8 0
3 years ago
Water is amphoteric. If it reacts with a compound that is a stronger acid than itself, water acts as a
kirza4 [7]

Answer:

Water acts as a base in the presence of a strong acid

Explanation:

Water,being an amphoteric compound, can act both as an acid and as a base.

In the presence of an acid , water acts as a base but in the presence of a base, water acts as an acid.

5 0
2 years ago
Determine the concentration of H+ ions in an aqueous solution where [OH-] =2.25 × 10^-4 M. I have 29 minutes I beg u guys pls hu
mixas84 [53]

but where Is the volume in order for us to determine the concentration. since we have moles in H+ ions

then you can say

concentration = M*1000/V

6 0
3 years ago
The. bond dissociation enthalpies of the H-H bond and the H-Cl bond are 435 kJ mol^-1 and 431 kJ mol^-1, respectively. The ΔHfO
Novay_Z [31]

The bond dissociation energy of the Cl - Cl bond is -958 kJ mol^-1.

<h3>What is the dissociation enthalpy?</h3>

Given that;

H-H bond energy =  435 kJ mol^-1

H-Cl bond energy = 431 kJ mol^-1

ΔHfO of HCL(g) = -92kJ mol^-1

Bond dissociation enthalpy of the Cl-Cl bond = x

-92 = 435  +  431 + x

x = -92 - (435  +  431)

x = -958 kJ mol^-1

Learn More about dissociation enthalpy:brainly.com/question/9998007?

#SPJ1

6 0
1 year ago
In the reaction H2SO4 + 2 NaOH -&gt; Na2SO4 + 2H2O, an equivalence point occurs when 29.43 mL of 0.1973 M NaOH is added to a 32.
Tamiku [17]
            moles NaOH = c · V = 0.1973 mmol/mL · 29.43 mL = 5.806539 mmol
            moles H2SO4 = 5.806539 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.9032695 mmol
Hence
            [H2SO4]= n/V = 2.9032695 mmol / 32.42 mL = 0.08955 M
The answer to this question is  [H2SO4] = 0.08955 M

6 0
2 years ago
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