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Paul [167]
3 years ago
7

Predict how heat would flow if beaker a is moved so that it is touching beaker b

Chemistry
1 answer:
Arlecino [84]3 years ago
7 0
Heat flows from hot to cold, therefore heat, denoted as q would flow from beaker A into beaker B
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Help please! -A compound contains 0.013 moles of carbon, 0.039 moles of hydrogen and 0.0065 moles of oxygen. Determine the empir
stepan [7]

A) C2H6O1

To find the emperical formula, divide each mole value by the smallest

For carbon, 0.013/0.0065 = 2

For hydrogen, 0.038/0.0065= 6

For oxygen, 0.0065/0.0065= 1

Emperical formula = C2H6O1

8 0
3 years ago
Read 2 more answers
Which statement describes the bonds in iron sulfate, FeSO4?
Feliz [49]

___

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Elements form bonds to increase their stability. The main types of bonds are:

  • Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
  • Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
  • Covalent bonds: they are formed between nonmetals, which share electrons.

Regarding the bonds in FesO₄:

  • Fe is a metal and S a nonmetal, thus they will form ionic bonds.
  • S and O are both nonmetals, thus they will form covalent bonds.

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Learn more: brainly.com/question/23882847

5 0
2 years ago
When a 2.00 g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 1.28 kJ ⋅ K − 1 , the tempe
Alchen [17]

Answer : The molar heat of solution of KCl is, 17.19 kJ/mol

Explanation :

First we have to calculate the heat of solution.

q=c\times (\Delta T)

where,

q = heat produced = ?

c = specific heat capacity of water = 1.28kJ/K

\Delta T = change in temperature = 0.360 K

Now put all the given values in the above formula, we get:

q=1.28kJ/K\times 0.360K

q=0.4608kJ=460.8J

Now we have to calculate the molar heat solution of KCl.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 460.8 J

m = mass of KCl = 2.00 g

Molar mass of KCl = 74.55 g/mol

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{2.00g}{74.55g/mole}=0.0268mole

Now put all the given values in the above formula, we get:

\Delta H=\frac{460.8J}{0.0268mole}

\Delta H=17194.029J/mol=17.19kJ/mol

Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol

7 0
3 years ago
Calculate the grams of CaCl2 necessary to make a 0.15Msolution.
xxTIMURxx [149]

Answer: mass m = M·c·V

Explanation: M(CaCl2) = 110.98 g/mol, c= 0.15 mol/l,

n=m/M= cV, volume of Solution is not mentioned

3 0
3 years ago
The _______ elements tend to lose electrons and form positive ions, while the _______ elements tend to gain electrons and form n
Jet001 [13]
Actions form positive ions while anions forms negative
7 0
4 years ago
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