Calculate the mole fraction of kbr (molar mass 119.00 g/mol) in a solution made by dissolving 0.30 g kbr in 0.400 l of H2O (d =
1 answer:
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Answer: c. +4
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here manganese is having an oxidation state of +4 called as cation and oxygen forms an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged to give which written in simplest whole number ratios to give neutral
Answer:
1.1 × 10⁻⁴ M
Explanation:
Let's consider the following double displacement reaction.
CuCl₂(aq) + 2 AgNO₃(aq) → 2 AgCl(s)+ Cu(NO₃)₂(aq)
We can establish the following relations:
- The molar mass of AgCl is 143.32 g/mol.
- The molar ratio of AgCl to CuCl₂ is 2:1
The moles of CuCl₂ that reacted to produce 7.7 mg of AgCl are:
The molarity of CuCl₂ is:
Answer:
26,167.47m
Explanation:
Problem:
We are to solve this problem using dimensional analysis:
from the given conversion factors-
0.621mi = 1.00km
1km = 1000m
From the problem, we are groing from miles to metres:
16.25mi x x
The mi will cancel out and also the km. This leaves us with the desired unit we want which is meters, m.
= 26,167.47m