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7nadin3 [17]
3 years ago
10

Imagine a balloon is made from a membrane that's permeable to water but not sucrose molecules. How would the concentration of su

crose inside the balloon be affected if the balloon is filled with a 50% sucrose solution and then placed in a beaker of water?
Chemistry
1 answer:
Blababa [14]3 years ago
4 0

Answer:

The concentration of sucrose will decrease.

Explanation:

The balloon contains 50% sucrose solution.

Diffusion is the net movement of the substance from the region of the higher concentration to the region of the lower concentration.

Given that the membrane is only permeable to water not sucrose. So, movement of sucrose will not take place. <u>When the balloon is placed in a beaker of water, by the process of diffusion, the water moves from beaker to balloon and thus, the balloon will expand and the concentration of sucrose solution will decrease.</u>

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Which of these are equal to 3.01 x 1023 particles 76.9 g of diatomic iodine (I2) 79.9 g of diatomic bromine (Br2) 6 g of carbon
solmaris [256]
To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:

<span>76.9 g I2  (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23

79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>

6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>

13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles

Therefore, the answers are Br2 and C.
3 0
3 years ago
How many grams of Chromium(III) nitrate are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate to produce chromiu
mina [271]

Grams of Chromium(III) nitrate produced : 268.95 g

<h3>Further explanation</h3>

Given

0.85 moles of Lead(IV) nitrate

Required

grams of Chromium(III) nitrate

Solution

Reaction

Balanced equation :

<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>

From the equation, mol ratio of Pb(NO₃)₄  : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃

mol Cr(NO₃)₃ =

\tt \dfrac{4}{3}\times 0.85=1.13

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :

mass = mol x MW

mass = 1.13 x 238.0108

mass = 268.95 g

7 0
3 years ago
What are the answers to the blanks to make this equation balanced
Eddi Din [679]

1Al+6NaOH==>2Na_{3}AlO_{3}+3H_{2}


Hope this helps!

5 0
4 years ago
What is the answer??
Leya [2.2K]

Covalent bonds are between two non-metals. Hydrogen and oxygen are non-metals. Hence is is, "yes, hydrogen and oxygen are nonmetals."


For the future, you might want to look at some videos to help you! :) (Tyler DeWitt is a really good chem you-tube teacher!)


7 0
3 years ago
Read 2 more answers
A pure gold metal bar displaces 0.82 L of water. What is the mass in kilograms? (the density of gold is 19.3 g/cm^3)
Ket [755]

Answer:

Mass of gold bar is 15.8 kg

Explanation:

The gold metal bar displaces volume of water equal to volume of metal bar.

So, volume of gold metal bar = 0.82 L

1cm^{3}=0.001L

We know that density is the ratio of mass to volume.

So mass of gold bar = (density of gold)\times(volume of gold bar) = (19.3\times0.82\times \frac{1}{0.001})g =15826 g

Now, 1 g = 0.001 kg

So mass of gold bar  = (15826\times 0.001) kg = 15.8 kg

6 0
4 years ago
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