To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:
<span>76.9 g I2 (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23
79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles
Therefore, the answers are Br2 and C.
Grams of Chromium(III) nitrate produced : 268.95 g
<h3>Further explanation</h3>
Given
0.85 moles of Lead(IV) nitrate
Required
grams of Chromium(III) nitrate
Solution
Reaction
Balanced equation :
<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>
From the equation, mol ratio of Pb(NO₃)₄ : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃
mol Cr(NO₃)₃ =

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :
mass = mol x MW
mass = 1.13 x 238.0108
mass = 268.95 g
Covalent bonds are between two non-metals. Hydrogen and oxygen are non-metals. Hence is is, "yes, hydrogen and oxygen are nonmetals."
For the future, you might want to look at some videos to help you! :) (Tyler DeWitt is a really good chem you-tube teacher!)
Answer:
Mass of gold bar is 15.8 kg
Explanation:
The gold metal bar displaces volume of water equal to volume of metal bar.
So, volume of gold metal bar = 0.82 L

We know that density is the ratio of mass to volume.
So mass of gold bar = (density of gold)
(volume of gold bar) = (
)g =15826 g
Now, 1 g = 0.001 kg
So mass of gold bar = (
) kg = 15.8 kg