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Anuta_ua [19.1K]
3 years ago
6

Which orbital is the first to fill with electrons in a given principal energy level?

Chemistry
2 answers:
frez [133]3 years ago
8 0
The s orbital is first to fill
zepelin [54]3 years ago
4 0

Answer:  s orbitals

Explanation:  s orbital is the first to fill with electrons in a given principal energy level.

It has the most penetrating power out of all the 4 orbitals.

There are 4 orbitals in which the electrons are filled regularly.These are s(sharp), p(principle), d(diffused) and f(fundamental).

S orbitals are near the nucleus . The electrons are filled as per Aufbau Principle.

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Setler [38]

Answer:

C

Explanation:

Because on the moon you are basically weightless and your mass would stay the same

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The following are formed as white precipitates in solution except
aniked [119]

Answer:

A. Iron (III) hydroxide

Explanation:

Orange-brown or rust

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Read 2 more answers
How do we balance Zn + HNO3 Zn(NO3)2 + NO + H20​
USPshnik [31]

3Zn + 8HNO₃⇒ 3Zn(NO₃)₂ + 2NO + 4H₂O

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  
  • 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:  

Balancing C atoms, H and the last O atoms

Reaction

Zn + HNO₃⇒ Zn(NO₃)₂ + NO + H₂O

  • 1. gives a coefficient

aZn + bHNO₃⇒ Zn(NO₃)₂ + cNO + dH₂O

  • 2. make an equation

Zn : left = a, right =1 ⇒a=1

H : left = b, right = 2d⇒ b=2d (eq 1)

N : left = b, right = 2+c⇒b=2+c (eq 2)

O : left = 3b, right = 6+c+d ⇒3b=6+c+d(eq 3)

  • From eq 1 and eq 3

3(2d)=6+c+d

6d=6+c+d

5d=6+c (eq 4)

  • From eq 2 and eq 3

3(2+c)=6+c+d

6+3c=6+c+d

2c=d (eq 5)

  • From eq 4 and eq 5

5(2c)=6+c

10c=6+c

9c=6

c = 2/3

  • input eq 5

d = 2 x 2/3

d = 4/3

  • input eq 1

b = 2 x 4/3

b = 8/3

The equation

aZn + bHNO₃⇒ Zn(NO₃)₂ + cNO + dH₂O to

Zn + 8/3HNO₃⇒ Zn(NO₃)₂ + 2/3NO + 4/3H₂O x 3

3Zn + 8HNO₃⇒ 3Zn(NO₃)₂ + 2NO + 4H₂O

8 0
3 years ago
Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,
torisob [31]

Answer : The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, K^+,NO_3^-

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

The ionic equation in separated aqueous solution will be,

2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)

In this equation, K^+\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)

4 0
3 years ago
MAGNESIUM (Mg)<br> +FLUORINE (F) =
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MgF2 magnesium fluoride

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